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2 years ago

When given a trinomial with no GCF what is the first step in factoring?

2 answers:

5 0

Step 1: Group the first two terms together and then the last two terms together. Step 2: Factor out a GCF from each separate binomial. Step 3: Factor out the common binomial. Note that if we multiply our answer out, we do get the original polynomial.

Elodia [21]2 years ago

4 0

Answer:

Group the first two terms together and then the last two terms together

Step-by-step

may not be right sorry if it isn't

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What is the inverse of the function h(x)=5+x/4-2x

deff fn [24]

Answer:

I believe you, Divide x x by 1 1 .

Step-by-step explanation:

Since g(h(x))=x g ( h ( x ) ) = x , h−1(x)=2x5−85 h - 1 ( x ) = 2 x 5 - 8 5 is the inverse of h(x)=52x+4 h ( x ) = 5 2 x + 4 .

sorry if im wrong

4 0

3 years ago

Can someone please answer these 4 questions they don’t look hard- but I just need to understand please!! (If you can provide the

Nostrana [21]

Answer:

Thanks for the points

Step-by-step explanation:

6 0

3 years ago

A soccer ball is kicked from 3 feet above the ground. the height,h, in feet of the ball after t seconds is given by the function

dexar [7]

Here's our equation.

$h=-16t+64t+3$

We want to find out when it returns to ground level (h = 0)

To find this out, we can plug in 0 and solve for t.

$0 = -16t+64t+3 \\ 16t-64t-3=0 \\ use\ the\ quadratic\ formula\ \frac{-b\±\sqrt{b^2-4ac}}{2a} \\ \frac{-(-64)\±\sqrt{(-64)^2-4(16)(-3)}}{2*16} = \frac{64\±\sqrt{4096+192}}{32}$

$= \frac{64\±\sqrt{4288}}{32} = \frac{64\±8\sqrt{67}}{32} = \frac{8\±\sqrt{67}}{4} = \boxed{\frac{8+\sqrt{67}}{4}\ or\ 2-\frac{\sqrt{67}}{4}}$

So the ball will return to the ground at the positive value of $\boxed{\frac{8+\sqrt{67}}{4}}$ seconds.

What about the vertex? Simple! Since all parabolas are symmetrical, we can just take the average between our two answers from above to find t at the vertex and then plug it in to find h!

$\frac{1}2(\frac{8+\sqrt{67}}{4}+2-\frac{\sqrt{67}}{4}) = \frac{1}2(2+\frac{\sqrt{67}}{4}+2-\frac{\sqrt{67}}{4}) = \frac{1}2(4) = 2$

$h=-16t^2+64t+3 \\ h=-16(2)^2+64(2)+3 \\ \boxed{h=67}$

8 0

3 years ago

What value of x satisfies this equation, 4/5 x - 6 = -2 ? Group of answer choices

andrew11 [14]

Answer:

Step-by-step explanation:

4/5 x -6 = -2

4 x -30 = -10

-120 = -10

5 0

2 years ago

Find the solution of the square root of the quantity of x plus 2 plus 4 equals 8, and determine if it is an extraneous solution

Iteru [2.4K]

Consider the equation:

$\sqrt{x+2}+4 = 8$

Subtracting '4' from both the sides of the equation, we get as

$\sqrt{x+2}+4-4= 8-4$

$\sqrt{x+2}= 4$

Squaring on both the sides of the equation, we get

$(\sqrt{x+2})^2 = (4)^2$

$x+2 = 16$

Subtracting '2' from both the sides of the equation, we get

$x+2-2=16-2$

x=14

Since, An extraneous solution is a solution that arises from the solving process that is not really a solution at all. But, in this equation x=14 is the solution of the given equation.

Hence, it is not an extraneous solution.

4 0

3 years ago

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