Ok , lots of questions=lower standard of explanation
just answers
5. 8.5 times 10^12
6. 0.001260-7,003,000
7.3.843 times 10^4
9. x=1
10. 7^(x+5)=49^(x+3)
11. 1.03
12. 25,700(0.85)^x
13. 10a√a
14.
![2 x^{2} y^{4} \sqrt[3]{5x^{2}}](https://tex.z-dn.net/?f=2%20x%5E%7B2%7D%20%20y%5E%7B4%7D%20%20%5Csqrt%5B3%5D%7B5x%5E%7B2%7D%7D%20)
15.6√3
16.

17.
![4 \sqrt[3]{x^{2}}](https://tex.z-dn.net/?f=%204%20%5Csqrt%5B3%5D%7Bx%5E%7B2%7D%7D%20)
18.

19.√109
20. (8,(3/2))
21. 5 units
Answer: the answers are the second one and the last one
Step-by-step explanation:
What is P(tails ) P(tails)start text, P, left parenthesis, t, a, i, l, s, end text, right parenthesis? If necessary, round your
blagie [28]
Question is not clear enough
I'll assume the question is this:
A fair coin has 2 sides (heads and tails) that are equally likely to show when the coin is flipped. What is P(tails)?
Answer:
P(tails) = 0.5
Step-by-step explanation:
Given:
Number of sides = 2
Number of head = 1
Number of tails = 1
Let P(Tail) = Probability of obtaining a tail when the coin is flipped.
P(Tails) is calculated as follows;
P(Tails) = Number of Tails/Total Number of Sides
Substitute in the values of Number of Tails and Total Number of Sides
P(Tails) = 1/2
P(Tails) = ½
P(Tails) = 0.5
Hence, the probability of obtaining a tail provided that the two sides of the coin are equally likely to show when the coin is flipped is 0.5
2,500 yea is that what you were looking for
Answer:
7.86 km
Step-by-step explanation:
Let x represent the distance point P lies east of the refinery. (We assume this direction is downriver from the refinery.)
The cost of laying pipe to P from the refinery (in millions of $) will be ...
0.5√(1² +x²)
The cost of laying pipe under the river from P to the storage facility will be ...
1.0√(2² +(9-x)²) = √(85 -18x +x²)
We want to minimize the total cost c. That total cost is ...
c = 0.5√(x² +1) +√(x² -18x +85)
The minimum value is best found using technology. (Differentiating c with respect to x results in a messy radical equation that has no algebraic solution.) A graphing calculator shows it to be at about x ≈ 7.86 km.
Point P should be located about 7.86 km downriver from the refinery.