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Levart [38]
3 years ago
15

Help with some questions please Brainilest answer !/

Mathematics
2 answers:
jenyasd209 [6]3 years ago
8 0
8.5 × 10^12 6.) .001260 - 7003000 7.) 3.843 × 10^5 9.) X=1 10.) 7 ^x + 5 = 49 ^ x + 3 11.) 3 12.) A (or the first one) 13.) The third one 14.) I would guess the third one 15.) The first one 16.) The last one 17.) The second one 18.) The third one 19.) The last one 20.) The last one 21.) The last one
murzikaleks [220]3 years ago
4 0
Ok , lots of questions=lower standard of explanation
just answers


5. 8.5 times 10^12
6. 0.001260-7,003,000
7.3.843 times 10^4
9. x=1
10. 7^(x+5)=49^(x+3)
11. 1.03
12. 25,700(0.85)^x
13. 10a√a
14. 2 x^{2}  y^{4}  \sqrt[3]{5x^{2}}
15.6√3
16. \frac{2 \sqrt{3x} }{3x}
17. 4 \sqrt[3]{x^{2}}
18.64 x^{ \frac{10}{3} }  y^{ \frac{5}{2} }
19.√109
20. (8,(3/2))
21. 5 units
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Fourteen is the correct answer
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3 years ago
A square rug covers 79 square feet of floor. What is the approximate length of one side of the rug? (Approximate to the nearest
Mice21 [21]
A = a^2.....where " a " is the length of one side
A = 79

79 = a^2...take sqrt of both sides, eliminating the ^2
sqrt 79 = a
8.89 = a

so the length of one side is approximately 8.89 ft <==
8 0
4 years ago
Find the average of these numbers to the nearest whole number. 516,497,501,528,476
defon

516+497+501+528+476= 2518

2518/5= 503.6

round up to 504

5 0
3 years ago
A coin is tossed 4 times. Let E1 be the event "the first toss shows heads" and E2 the event "the second toss shows heads" and so
Elden [556K]

Answer:

The events are independent.

The probability of showing heads on both toss is equal to 1/2

Step-by-step explanation:

The sample space for this experiment consists of 2⁴= 16 sample points, as each toss can result in two outcomes we assume that the events are equally likely.

Two events are independent in the sample space if the probability of one event occurs, is not affected by whether the other event has or has not occurred.

In general the k events are defined to be mutually independent if and only if the probability of the intersection of  any 2,3,--------, k  equals the product of their respective probabilities.

P (A∩B) = P(A). P(B)

P (A∩B)   = 1/2. 1/2= 1/4

                                                                  Head          Tail

 P(E1)= 1/2  ----------          Coin 1               H,H              T,H

                                                                1/4                  1/4

  P(E2)= 1/2  ---------------  Coin 2             H, H               H,T

                                                                      1/4           1/4

So the events are independent.

The probability of showing heads on both toss is equal to 1/2

The sample space for this experiment consists of 2⁴= 16 sample points, out of which eight will have heads on both toss.

Or in other words ( 1/4* 1/4) = 2/4 = 1/2

4 0
3 years ago
What is the 75th term of the sequence -200,-100,0
worty [1.4K]

Answer:

7200

Step-by-step explanation:

5 0
3 years ago
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