Equation of a circle with center at (h,k) and radius of r is
(x-h)²+(y-k)²=r²
so
center (-7,10) and diameter 6
remember, diameter/2=radius=6/2=3
so
equation is (x-(-7))²+(y-10)²=3²
(x+7)²+(y-10)²=9
To write an equation in slope intercept form given the slope and a point, plug into point-slope form.
(y - y1) = m(x - x1)
In this equation, m is your slope and (x1, y1) is your point. If you follow this and solve for y, you will get your equation in slope intercept form.
11.5
Mark brainliest please
Hope this helps you
<span>8-(-5)-4 (-7)
=8+5-4-7
=2</span>
