The answer is #2 you’re welcome
The answer to the question is d
To answer this question, you first need to know what SohCahToa is.
S- opposite over hypotenuse
C- adjacent over hypotenuse
T- opposite over adjacent
In this situation, they have made it easier for you as they have given you the quotient of the opposite and adjacent sides (3.4) . Now in order to find an angle, you take the inverse of your expression. So instead of just Tan, you would plug in Tan^-1. So plug it in:
Tan^-1 (3.4)
Answer is 73.6 degrees.
Answer:
answer is B
Step-by-step explanation:
............
I started by labeling the right angle (Angle C) 90º. Next, I wrote down everything in one equation.
2x + 90 + 3x - 20 = 180º (180 degrees in a triangle)
Next, I add 20 on both sides.
2x + 90 + 3x = 200º
I combine like terms (2x and 3x)
5x + 90 = 200º
I subtract 90 from both sides.
5x = 110º
Divide 110 by 5 to get x.
x = 22
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For problem two, I label all the angles I know.
49º + 80º + r = 180º
I add 80 and 49.
129º + r = 180º
I subtract 180 and 129 and get 51º, which is your angle for R.
For angle X, you know that angle R plus angle X equals half of a circle, which is 180º
We know from before that 129º is 180º without R, so X is 129º
I hope this helps! Let me know if I'm wrong!
