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Nimfa-mama [501]
4 years ago
9

-3x-4(x-1)=5(2x+1)+6x

Mathematics
1 answer:
Firdavs [7]4 years ago
6 0

Answer:

x = (-1)/23

Step-by-step explanation:

Solve for x:

-3 x - 4 (x - 1) = 5 (2 x + 1) + 6 x

-4 (x - 1) = 4 - 4 x:

4 - 4 x - 3 x = 5 (2 x + 1) + 6 x

Grouping like terms, -3 x - 4 x + 4 = 4 + (-3 x - 4 x):

4 + (-3 x - 4 x) = 5 (2 x + 1) + 6 x

-3 x - 4 x = -7 x:

-7 x + 4 = 5 (2 x + 1) + 6 x

5 (2 x + 1) = 10 x + 5:

4 - 7 x = 10 x + 5 + 6 x

Grouping like terms, 10 x + 6 x + 5 = (10 x + 6 x) + 5:

4 - 7 x = (10 x + 6 x) + 5

10 x + 6 x = 16 x:

4 - 7 x = 16 x + 5

Subtract 16 x from both sides:

4 + (-7 x - 16 x) = (16 x - 16 x) + 5

-7 x - 16 x = -23 x:

-23 x + 4 = (16 x - 16 x) + 5

16 x - 16 x = 0:

4 - 23 x = 5

Subtract 4 from both sides:

(4 - 4) - 23 x = 5 - 4

4 - 4 = 0:

-23 x = 5 - 4

5 - 4 = 1:

-23 x = 1

Divide both sides by -23:

Answer:  x = (-1)/23

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3 years ago
The length of a rectangle is increasing at a rate of 6 cm/s and its width is increasing at a rate of 5 cm/s. When
atroni [7]

Answer:

The area of the rectangle is increasing at a rate of 84 square centimeters per second.

Step-by-step explanation:

The area for a rectangle is given by the formula:

A=w\ell

Where <em>w</em> is the width and <em>l</em> is the length.

We are given that the length of the rectangle is increasing at a rate of 6 cm/s and that the width is increasing at a rate of 5 cm/s. In other words, dl/dt = 6 and dw/dt = 5.

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By the Product Rule:

\displaystyle \frac{dA}{dt}=\frac{dw}{dt}\ell +\frac{d\ell}{dt}w

Since we know that dl/dt = 6 and that dw/dt = 5:

\displaystyle \frac{dA}{dt}=5\ell + 6w

We want to find the rate at which the area is increasing when the length is 12 cm and the width is 4 cm. Substitute:

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The area of the rectangle is increasing at a rate of 84 square centimeters per second.

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