Ok, so user says that it should be solve for vertex not vertex form
(x,y)
to find the vertex of
y=ax^2+bx+c
the x value of the vertex is -b/2a
the y value is found by plugging in the x value for the vertex back into the original equation and evaluating
y=-2x^2-12x-28
a=-2
b=-12
xvalue of vertex is -(-12)/(2*-2)=12/-4=-3
x value of vertex is -3
plug backin for x
y=-2x^2-12x-28
y=-2(-3)^2-12(-3)-28
y=-2(9)+36-28
y=-18+8
y=-10
yvalue is -10
x value is -3
vertex is (-3,-10)
8/3=3x (cross multiplied to get this)
X=8/9 (divided both sides by 3)
Hope this helps :)
Answer:
False
Step-by-step explanation:
numbers are integers, the integers are negative, zero and positive,
while natural numbers are only positive,
therefore the statement is false
. False. Integers comprise negative and positive numbers (...- 3, -2, -1, 0, 1, 2, 3 ...) and natural numbers only comprise positive integers (0, 1, 2, 3 ...)
