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3 years ago

ABDC is an isosceles trapezoid. Given only the choices below, which properties would you use to prove ACD ≅ BDC by SSS?

1 answer:

8 0

If the choices are the following:
The legs are congruent.
The base angles are congruent.
The bases are | |.
<span>The diagonals are congruent.
Then , to prove </span>ACD ≅ BDC by SSS I would use The base angles are congruent.
<span>This is sufficient to prove the triangles are congruent.</span>

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Jayla recently accepted a new job earning $15.50 per hour. Last month, Jayla earned $2294 after four weeks of work. How many hou

V125BC [204]

Assuming the pay last month was from Jayla's new job, it represents pay for weekly hours of ...

$\dfrac{\$2294}{4\,week}\times\dfrac{1\,hours}{\$15.50}=37\,\dfrac{hours}{week}$

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4 0

3 years ago

Please help if you can :)

mojhsa [17]

a) n² + 6

n=1

1² + 6 = 1 + 6 =7

n=2

2² + 6 = 4 + 6 = 10

n=3

3² + 6 = 9 + 6 =15

n=4

4² + 6 = 16 + 6 =22

7, 10, 15, 22

n=10

10² + 6 = 100 + 6 =106

10 th term-106

b) 3n²

n=10

3 x 10² = 3 x 100= 300

10th term- 300

Hope this helps!

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2 years ago

Daniel wants to have a 90 average in his math class at the end of the year. He is trying to determine what he needs to get on hi

morpeh [17]

Exam + Tests + Quizzes + HW + Projects = 90

Exam = 10% * grade (x) = 0.1 * x

Tests = 50% * 85 = 0.5 * 85 = 42.5

Quizzes = 15% * 95 = 0.15 * 95 = 14.25

HW = 15% * 98 = 0.15 * 98 = 14.7

Projects = 10% * 92 = 0.1 * 92 = 9.2

Exam + Tests + Quizzes + HW + Projects = 90

(0.1 * x) + 42.5 + 14.25 + 14.7 + 9.2 = 90

(0.1 * x) + 80.65 = 90 (subtract 80.65 from each side)

(0.1 * x) = 9.35 (divide 0.1 from each side)

(0.1 * x)/0.1 = 9.35/0.1

x = 0.935

The answer is 93.5%

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2 years ago

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Four water tanks can hold a total of 432.4 gallons of water. On average, how much water can one tank hold? How much water is in

tekilochka [14]

432.2 / 4 = 108.1 <== avg of what 1 tank holds
1/2 full = 108.1/2 = 54.05

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3 years ago

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2(2x-1)=√8 how do i solve this step by step?

Mekhanik [1.2K]

First you would need to apply the distributive property on the left side to get rid of the parenthesis. Then, you would need to apply the square root on both sides of the equation. Once this is done you would just need to solve for x.

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3 years ago