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Oksana_A [137]
3 years ago
12

What is the leading coefficient of the function f(x)= 3x^5+6x^4-x-3

Mathematics
1 answer:
Natali5045456 [20]3 years ago
4 0

3. The leading coefficient of the function f(x)= 3x⁵+6x⁴-x-3 is 3.

For the function  f(x)= 3x⁵+6x⁴-x-3 , the highest power of x is 5, so the degree is 5. The leading term is the term containing that degree, 3x⁵. The leading coefficient is the coefficient of that term, 3.

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Factor f(x) = 15x^3 - 15x^2 - 90x completely and determine the exact value(s) of the zero(s) and enter them as a comma separated
Illusion [34]

Answer:

x=-2,0,3

Step-by-step explanation:

We have been given a function f(x)=15x^3-15x^2-90x. We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

15x^3-15x^2-90x=0

Now, we will factor our equation. We can see that all terms of our equation a common factor that is 15x.

Upon factoring out 15x, we will get:

15x(x^2-x-6)=0

Now, we will split the middle term of our equation into parts, whose sum is -1 and whose product is -6. We know such two numbers are -3\text{ and }2.

15x(x^2-3x+2x-6)=0

15x((x^2-3x)+(2x-6))=0

15x(x(x-3)+2(x-3))=0

15x(x-3)(x+2)=0

Now, we will use zero product property to find the zeros of our given function.

15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0

15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0

\frac{15x}{15}=\frac{0}{15}\text{ (or) }x-3=0\text{ (or) }x+2=0

x=0\text{ (or) }x=3\text{ (or) }x=-2

Therefore, the zeros of our given function are x=-2,0,3.

7 0
4 years ago
Y=x^2-4x-3<br> y=-2x^2-5x+1
Serggg [28]

Hi! This is the solution of your equation!

Download docx
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Answer:

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Step-by-step explanation:

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Answer:

x = 99°

y = 91°

Step-by-step explanation:

For Cyclic quadrilateral, the sum of the opposite angles = 180°

Let's find x :-

x + 81° = 180°

x = 180 - 81

x = 99°

Let's find y :-

y + 89° = 180°

y = 180 - 89

y = 91°

Hope this helps you !

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2 years ago
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