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EastWind [94]
3 years ago
15

Let X and Y again be uniformly distributed independent random variables on [0, 1]. a) Compute the expected value E(XY ). b) What

is the probability density function fZ(z) of Z = XY ? Hint: First compute the cumulative distribution function FZ(z) = P(Z ≤ z) using a double integral, and then differentiate in z. c) Use your answer to b) to compute E(Z). Compare it with your answer to a)

Mathematics
1 answer:
Mariulka [41]3 years ago
7 0

Answer:

a) Computing the expected value E(XY) gives 1/4

b) The probability density function fZ(z) of Z = XY is calculated in the attached picture.

c) Computing E(Z) gives 1/4

Step-by-step explanation:

Comparing the computation of E(Z) using the answer to b), it shows that the values are equal.

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8x{[(7+4)x2] - [(11-7)x4]}
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PEMDAS
P - Parentheses (or other grouping symbols)
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8x[(7+4)x^2] - [(11-7)x^4]\\  \\ 8x[(11)x^2] - [(4)x^4] \\  \\ 8x[11x^2] - [4x^4] \\  \\ 88x^3 - 4x^4 \\  \\ -4x^4+88x^3

If you then want to go on to factor it, your answer would be -4x^3(x-22)
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Find the sum<br> (4 - n) + 2(-5n + 3)
Assoli18 [71]

Answer:

−11n + 10

Step-by-step explanation:

(4-n) + 2 (-5n+3)

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The answer:-11n+10

6 0
3 years ago
Which of the following points would be a solution to this system of linear inequalities? ​
pychu [463]

Let's plug in both x and y values in the equation and check if the inequality is true...

\red{ \rule{35pt}{2pt}} \orange{ \rule{35pt}{2pt}} \color{yellow}{ \rule{35pt} {2pt}} \green{ \rule{35pt} {2pt}} \blue{ \rule{35pt} {2pt}} \purple{ \rule{35pt} {2pt}}

(4,1) \\ y \leqslant x + 1 \\ y <  -  \frac{x}{2}  - 1

Substitute x as 4 and y as 1

1 \leqslant 4 + 1 \\ 1 <  -  \frac{4}{2}  - 1

0  \leqslant  4 + 1 \\ 1 <  - 2 - 1

0 \leqslant 5 \\ 1 <  - 3

  • <em>This is not a solution because both are not true, Only one equation is giving true as answer which is not correct!~</em>

\purple{ \rule{300pt}{3pt}}

(0, - 3) \\ y \leqslant x + 1 \\ y <  -  \frac{x}{2}  - 1

Substitute x as 0 and y as -3

- 3 \leqslant 0 + 1 \\  - 3 <  -  \frac{0}{2}  - 1

- 3 \leqslant 1 \\  - 3 <  - 0 - 1

- 3 \leqslant 1 \\  - 3 <  - 1

  • <em>This is a solution because both are true, </em><em>Both the </em><em>equations</em><em> </em><em>are</em><em> </em><em>true</em><em> </em><em>which</em><em> </em><em>means</em><em> </em><em>the</em><em> </em><em>ordered</em><em> </em><em>pair</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>solution</em><em>!</em><em>~</em>

<u>Thus</u><u>,</u><u> </u><u>Option</u><u> </u><u>B</u><u> </u><u>(</u><u>0</u><u>,</u><u>-</u><u>3</u><u>)</u><u> </u><u>is</u><u> </u><u>the</u><u> </u><u>correct</u><u> </u><u>choice</u><u>.</u><u>.</u><u>.</u><u>.</u>

6 0
3 years ago
2+2 +2x2x7x2+13 —————————-
Rashid [163]

Answer:

73

Step-by-step explanation:

2×2×7×2=56

2+2=4

56+4+13=73

4 0
3 years ago
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