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nalin [4]
3 years ago
6

Please help asap!!!

Mathematics
1 answer:
Ganezh [65]3 years ago
4 0
Take a better pic plz
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Thomas reads 2/9 of a book on Monday and 1/6 of it on Tuesday. He reads twice as many pages on Wednesday as on Tuesday. What fra
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1/18 is left. Thomas has 1/18 left of his book. How? What denominator can 9&6 relate to? 54? Sure, but it could be lower. How about 18? Ok. We have 18 because 9x2 and 6x3 both equal 18... 2/9 becomes 4/18 because 18 divided by 9 is 2. You multiply 2 with the two from 2/9. 1/6 becomes 3/18 because 18 divided by 6 is 3. You then multiply 3 with the one from 1/6. Put it together and TA-DA... Your answer is 1/18
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4 years ago
Please help with this I am very stuck because I am horrible at math
tigry1 [53]

Answer:

20

Step-by-step explanation:

6 0
3 years ago
What is the probability that a marble chosen at random is
Brums [2.3K]

Answer:

P=\frac{6}{11}

Step-by-step explanation:

The probability can be defined as the ratio between the possible events and the total number of outcomes.

In this case, according to the image attached, the total number of outcomes is 11, because they are 11 marbles in total.

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P=\frac{6}{11}

The right answer is the last choice.

4 0
4 years ago
Read 2 more answers
The product of two numbers is 192. what is the minimum value of the sum of the first value plus twice the second value
VARVARA [1.3K]
Let x and y be the two positive numbers. -  Their product is 192: x *  y  =  192   equation 1

-  the sum of the first plus twice the second is a minimum:  x + 2y

<span>From the first equation, y =  192 / x. 
Substitute that into the second equation:
</span>
 x + 2y = x + 2(<span>192/x ) = x + 384/x

</span>f(x) is minimum when f'(x) = 0 and f"(x) > 0 

f(x)= <span>x + 384/x
</span>
f(x) = 1-384/x^2 

<span>1-384  / x^2 =  0 

x^2-384 = 0 

x^ 2= 354
 x = radical  354    = 18.8  here i'm confused why the number is decimal
???/ 
</span>

4 0
4 years ago
Help picture below problem 13
Hitman42 [59]

Answer:

it's obtuse angle...

mark me brainliest

3 0
2 years ago
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