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den301095 [7]
2 years ago
5

Help me fast I’ll mark brainliest plzzz

Mathematics
2 answers:
DanielleElmas [232]2 years ago
5 0

Answer:

1 2 3 4 5 6 7 8 9 10 11

Step-by-step explanation:

olga nikolaevna [1]2 years ago
5 0

Answer:

Since I don't have the numbers to plot, I'll tell you where to begin

Step-by-step explanation:

When plotting temperatures, it's important to remember positives and negatives

It's always a good idea to start by marking the halfway point as zero

Then, if the numbers are  in the tens, make each increment an increasing value of ten/-ten in each direction.

If they're low, (in the ones digits) then just mark the numbers on the increments in the positive/negative directions

Hope this helps!

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According to records, the amount of precipitation in a certain city on a November day has a mean of inches, with a standard devi
Mekhanik [1.2K]

Answer:

The probability that the mean daily precipitation will be of X inches or less for a random sample of n November days is the p-value of Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}, in which \mu is mean amount of inches of rain and \sigma is the standard deviation.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question:

Mean \mu, standard deviation \sigma

n days:

This means that s = \frac{\sigma}{\sqrt{n}}

Applying the Central Limit Theorem to the z-score formula.

Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

What is the probability that the mean daily precipitation will be of X inches or less for a random sample of November days?

The probability that the mean daily precipitation will be of X inches or less for a random sample of n November days is the p-value of Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}, in which \mu is mean amount of inches of rain and \sigma is the standard deviation.

5 0
2 years ago
4x+5&gt;49<br> what is the answer to this
Illusion [34]

Answer:

any big number

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Find all the real square roots of 9/16
Rainbow [258]

Answer:

0.1875

Step-by-step explanation:

NO EXPLANATION

°^°

8 0
2 years ago
anthonyś yearly budget for the furniture in his house is $18,000 he spent 9% of the budget on the family room how much did he sp
nata0808 [166]

Answer:

  $1620

Step-by-step explanation:

  9% of budget = 0.09 × $18000 = $1620

Anthony spent $1620 on the family room.

3 0
3 years ago
Help Me for number 1 &amp; 2
mafiozo [28]
This may not be correct but Georgia will be about nine if u subtract 6 from 15... And as for Jerry, if he swims for 4 hours, at 2 miles, he might be swimming 480 miles.. 2x60 (aka and hour x 2) 120.. Do that 4 times and u end up with about 480.. So sorry if I'm wrong
6 0
3 years ago
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