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mr_godi [17]
3 years ago
15

Suppose a student reaches in the bag and randomly selects nine red chips and eleven yellow chips. Based on this sample, what is

a good estimate for the percentage of enrolled university students that are male?
Mathematics
2 answers:
Marysya12 [62]3 years ago
3 0
The good estimate would be 9/20 and 11/20=20/20
jekas [21]3 years ago
3 0

Answer:

<h2>A good estimate would be</h2>

\frac{9}{20} and \frac{11}{20}.

Step-by-step explanation:

To solve this problem, you can find the probability of each case, red chips and yellow chips, which are gonna be simple probabilities, that is, the quotient between the number of events and the number of possible outcomes.

We know that the student reaches nine red chips out of 20, the probability is

P_{red}=\frac{9}{20}

Also, the students reaches eleven yellow chips out of 20, so

P_{yellow} =\frac{11}{20}

Thefeore, a good estimate would be \frac{9}{20} and \frac{11}{20}.

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7 0
3 years ago
Greg and Erin start at the same point and begin running in different directions. Greg is running east at a speed of 7 miles per
AveGali [126]

Answer: The time at which the distance between the two is 150 miles is 1.3 hr.

Step-by-step explanation:

Step 1: Sketch the problem as shown in the attached image.

The problem can be solved using Pythagoras theorem since the sketch is a right angled triangle.

It follows the equation x² + y² = 15².

The distance covered by Greg is given by <em>x mi</em>, and that of Erin is given by <em>y mi</em>.

Step 2: To derive the distance covered by Erin and Greg, we use the formula <em>Speed = distance ÷ time.</em>

Which by cross-multiplying gives <em>distance = speed × time</em>.

Let time taken to cover the distance be <em>t h</em>.

Given that Speed of Erin is 9 mph and that of Greg is 7 mph.

Hence, distance covered by Greg, x = 7 × t = 7t.

Distance covered by Erin, y = 9 × t = 9t.

Step 3: Insert the terms x and y into the Pythagoras equation x² + y² = 15² and solve for <em>time t.</em>

(7t)² + (9t)² = 15²

49t² + 81t² = 225

(49 + 81)t² = 225

      t² = 225/(49 + 81)

      t² = 225/130

      t² = 1.730769231

       t = √1.730769231

       t = 1.315587029

t = 1.3hr

Hence the time at which the distance between the two is 150 miles is 1.3 hr.

4 0
3 years ago
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Answer: (x – 1)(x + 1)(x + 5) = 0

x – 1 = 0, so x =  1

x + 1 = 0, so x =  -1

x + 5 = 0, so x = -5

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