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devlian [24]
3 years ago
7

The circle C has centre A(2,1) and passes through the point B(10,7). Find and equation for C

Mathematics
1 answer:
Semmy [17]3 years ago
7 0
The equation of a circle:
(x-h)^2+(y-k)^2=r^2
(h,k) - the coordinates of the centre
r - the radius

A(2,1) - \hbox{the centre} \\
h=2 \\ k=1 \\ \\
(x-2)^2+(y-1)^2=r^2 \\ \\
\hbox{passes through B(10,7)} \\
x=10 \\
y=7 \\ \\
(10-2)^2+(7-1)^2=r^2 \\
8^2+6^2=r^2 \\
64+36=r^2 \\
r^2=100 \\ \\
\hbox{the equation:} \\ \boxed{(x-2)^2+(y-1)^2=100}
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Answer:

The angle between [A_F] and the base of the cone = 68.2°

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Step-by-step explanation:

The given parameters are;

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The base radius of the cone  = 2 m

The angle which the A\hat OC = 120°

Therefore, we have;

The angle between [A_F] and the base of the cone = The angle between [CF]  and the base of the cone

The angle between [CF]  and the base of the cone = tan⁻¹(5/2) = tan⁻¹(2.5) ≈ 68.2°  

∴ The angle between [A_F] and the base of the cone = The angle between [CF]  and the base of the cone = 68.2°

The angle between [A_F] and the base of the cone = 68.2°

The area of the base of the cone = π × r² = π × 2² = 4·π ≈ 12.57

The area of the base of the cone ≈ 12.57 m².

8 0
3 years ago
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Answer:

see explanation below

Step-by-step explanation:

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4 0
2 years ago
A line is drawn through (-7, 11) and (8.-9). The equation
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Step-by-step explanation:

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Step-by-step explanation:

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2 years ago
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