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Agata [3.3K]
3 years ago
6

Find the slope of a line that is vertical and passes through the point (-1,2)

Mathematics
1 answer:
Greeley [361]3 years ago
3 0

Answer:

slope: undefined

Step-by-step explanation:

vertical line slope = (y-y') / (x-x')

x-x' = 0

slope: undefined

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Question 11 (1 point)<br> (02.05 LC)<br> What number is 60% of 80?<br> Input only whole numbers.
sweet [91]

Answer:

48

Step-by-step explanation:

60% of 80 is 48

5 0
2 years ago
In a survey of sleeping habits, 8400 adults were selected randomly and contacted by telephone. Based on a medical association's
Andreas93 [3]

Answer:

d. None of the above.

Step-by-step explanation:

<em>a. By the law of large numbers, it would again be 46%. </em>

FALSE. This proportion (46%) is a sample statistic, that can or can not be repeated in another sample.

<em>b. By the law of large numbers, the smaller (second) survey will certainly produce a sample proportion farther from the true population proportion than the larger (first) survey. </em>

FALSE. Smaller samples will produce wider confidence intervals for the estimation of the population proportion, but larger samples does not necessarily gives us better point estimations of the true proportion. A small sample can be closer to the true proportion than a large sample, although is less probable.

<em>c. The proportion computed from the sample of 5000 people would be more accurate because smaller samples tend to be more homogeneous than larger samples. </em>

FALSE. There is no evidence to claim that smaller samples are more homogeneous.

<em>d. None of the above.</em> TRUE

6 0
3 years ago
How many 1/3 cup servings of raisins are in 1/2 a cup of raisins?
sp2606 [1]
1 1/2 or 3/2 because 1/2 divided by 1/3 is equal to that

6 0
3 years ago
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PLS HELP WILL MARK BRAINLIEST, PLS HURRY
irina1246 [14]

Answer:

B

Step-by-step explanation:

3 0
2 years ago
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It’s a precalculus holiday equation. Need to simplify to find the “secret message” can anyone help???
tensa zangetsu [6.8K]

Take the expression in chunks:

>>

((X+A)(X-A)M+A^2M)E=((X^2-A^2)M+A^2M)E=X^2ME

>>

\dfrac{\frac{R+X}X+\frac X{R-X}}{\frac X{R-X}}=\dfrac{\frac{R+X}X}{\frac X{R-X}}+1

\dfrac{\frac{(R+X)(R-X)}{X(R-X)}}{\frac{X^2}{X(R-X)}}=\dfrac{(R+X)(R-X)}{X^2}=\dfrac{R^2-X^2}{X^2}=\dfrac{R^2}{X^2}-1

\implies\dfrac{\frac{R+X}X+\frac X{R-X}}{\frac X{R-X}}=\dfrac{R^2}{X^2}

>>

Note that (a+b)^2-(a-b)^2=(a^2+2ab+b^2)-(a^2-2ab+b^2)=4ab. So

\displaystyle\frac{4AS}3\sum_{\rm cyc}\frac1{X((E+Y)^2-(E-Y)^2)}=\frac{4AS}3\sum_{\rm cyc}\frac1{4XEY}=\frac{AS}3\sum_{\rm cyc}\frac1{XEY}

where the cyclic sum notation means

\displaystyle\sum_{\rm cyc}f(x,y,z)=f(x,y,z)+f(z,x,y)+f (y,z,x)

In other words, we take the sum over all possible cycles of the sequence of arguments to the summand. The second square-bracketed chunk reduces to

\displaystyle\frac{AS}3\sum_{\rm cyc}\frac1{XEY}=\frac{AS}3\left(\dfrac1{XEY}+\dfrac1{EYX}+\dfrac1{YXE}\right)=\dfrac{AS}3\dfrac3{XEY}=\dfrac{AS}{XEY}

So to recap, we've reduced the starting expression to

X^2ME\left(\dfrac{R^2}{X^2}-\dfrac{AS}{XEY}\right)Y

>>

\dfrac{R^2}{X^2}-\dfrac{AS}{XEY}=\dfrac{R^2EY-ASX}{X^2EY}

Finally, we have

X^2ME\dfrac{R^2EY-ASX}{X^2EY}Y=M(R^2EY-ASX)

Then distributing M and rewriting to decode the message, we have

MERRY-XMAS

6 0
3 years ago
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