Question

At 5:00 a.m., the temperature outside was 66° F. By noon, the temperature had risen to 87° F. Which equation models the temperature y at time x?

Answer 1

Answer: Equation representing the temperature y at time x is

$y=3x+51$

Step-by-step explanation:

Since we have given that

At 5:00 a.m., the temperature outside was 66° F.

At x = 5, y = 66

By noon, the temperature had risen to 87° F.

At x = 12, y = 87

We will find "Slope of line first ":

$m=\dfrac{y_2-y_1}{x_2-x_1}\\\\m=\dfrac{87-66}{12-5}\\\\m=\dfrac{21}{7}\\\\m=3$

So, Equation that models the temperature y at time x would be

$(y-66)=3(x-5)\\\\y-66=3x-15\\\\y=3x-15+66\\\\y=3x+51$

Hence, equation representing the temperature y at time x is

$y=3x+51$

Answer 2

If so, 87 - 66 = 21 / (12-5) = 3 degrees Fahrenheit per hour.