She is incorrect. It doesn’t matter what sides you label a or b but c matters. The longest side (the hypotenuse) is always c.
You got this you can do it I don’t know the answer but I hope you find someone who does(:
if those are fractions being five and two thirds etc... I believe it would be 17/6. if you convert to improper fractions and then get a common denominator to subtract that should do it. Hope that helps.
There isn't a specific number so i'll just list all of them.
2 : 100 millions
3 : 10 millions
4 : millions
5 : 100 thousands
0 : 10 thousands
0 : thousands
4 : hundreds
5 : tens
0 : ones
9514 1404 393
Answer:
(d) 5a²
Step-by-step explanation:
![\displaystyle\sqrt[3]{125a^6}=\sqrt[3]{5^3a^6}=\sqrt[3]{(5a^2)^3}=\boxed{5a^2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Csqrt%5B3%5D%7B125a%5E6%7D%3D%5Csqrt%5B3%5D%7B5%5E3a%5E6%7D%3D%5Csqrt%5B3%5D%7B%285a%5E2%29%5E3%7D%3D%5Cboxed%7B5a%5E2%7D)
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The applicable rules of exponents are ...
(a^b)^c = a^(bc)
∛a = a^(1/3)