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shtirl [24]
3 years ago
12

Solve the system 4x + 2y = 10 x = y + 13

Mathematics
2 answers:
solniwko [45]3 years ago
4 0

Answer:  (6,-7)

Step-by-step explanation:

4x +2y = 10  

x = y + 13      Substitute the value of x into the first equation to solve for y.

4(y + 13) +2y = 10   apply the distributive property on the left side

4y + 52 + 2y = 10   Combine like terms on the left side

6y + 52 =  10    Subtract  52 from both sides

       -52     -52

6y = -42  

y= -7  

The value of y so input it into one of the equations to solve for x

4x + 2(-7) = 10  

4x - 14  =  10

       +14    +14

4x = 24

x= 6

Maslowich3 years ago
3 0

Answer:

x = 6

y = -7

Step-by-step explanation:

We have the system of equations:

4x+2y=10\\x=y+13

Let's solve by substituting. We know that x=y+13, so we can substitute y+13 in as x in the equation 4x+2y=10.

4(y+13) + 2y = 10

Simplify this down so that we have y on one side of the equation:

4y + 52 + 2y = 10\\\\6y + 52 = 10\\\\6y = -42\\\\y = -7

Now that we know the value of y, we can substitute it in to the equation x = y+13 to find x.

x = -7+13\\\\x = 6

Hope this helped!

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Describe the error then simplify the expression correctly.<br><br> -5(3+6)=-15+30<br> =15
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Answer: 30 should be negative

Step-by-step explanation:

when having an equation like that, you must multiply -5 by 3, which equals to -15, then multiply-5 by 6 which then equals to -30. The correct equation should be -5(3+6)= -15+-30= -45


I think this should be correct, hope this helps!

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2 years ago
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Which expressions are equivalent when y = 2 and y = 5? 2 y minus 1 and 3 y minus 5 + y 5 y + 4 and 7 y + 4 minus 2 y y + 7 and y
noname [10]

<u><em>Answer:</em></u>

Option b

<u><em>Explanation:</em></u>

The question is shown in the attached image

To answer this question, we will simply substitute in the given expressions with the values y=2 and y=5

The correct option will be the one having equal vales in both cases

<u>1. Option a:</u>

<u>At y = 2:</u>

2y - 1 = 2(2) - 1 = 3

3y - 5 + y = 3(2) - 5 + 2 = 3

<u>At y = 5:</u>

2y - 1 = 2(5) - 1 = 10

3y - 5 + y = 3(5) - 5 + 5 = 15

This option is <u>incorrect</u>, since both expressions are not equal at y = 5

<u>2. Option b:</u>

<u>At y = 2:</u>

5y + 4 = 5(2) + 4 = 14

7y + 4 - 2y = 7(2) + 4 - 2(2) = 14

<u>At y = 5:</u>

5y + 4 = 5(5) + 4 = 29

7y + 4 - 2y = 7(5) + 4 - 2(5) = 29

This option is <u>correct</u>, since both expressions are equal at the two vales of y

<u>3. Option c:</u>

<u>At y = 2:</u>

y + 7 = 2 + 7 = 9

y + 2 + y = 2 + 2 + 2 = 6

<u>At y = 5:</u>

y + 7 = 5 + 7 = 12

y + 2 + y = 5 + 2 + 2 = 12

This option is <u>incorrect</u>, since both expressions are not equal at y = 2

<u>4. Option d:</u>

<u>At y = 2:</u>

3y - 4 = 3(2) - 4 = 2

3y - 2 + y = 3(2) - 2 + 2 = 6

<u>At y = 5:</u>

3y - 4 = 3(5) - 4 = 11

3y - 2 + y = 3(5) - 2 + 5 = 18

This option is <u>incorrect</u>, since both expressions are neither equal at y = 2 or y = 5

Hope this helps :)

8 0
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Help I will make you a brainllest :)
Zielflug [23.3K]

Answer:

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Step-by-step explanation:

Since m∠2 is 40°, then the m∠1 is also 40°. With that, ∠1 and ∠5 are supplementary, so we have 180 - 40 = 140°

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