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weqwewe [10]
3 years ago
15

What number is it? the difference of 9 and three times equals 69. find the number

Mathematics
1 answer:
Mazyrski [523]3 years ago
8 0
Consider the number as 'n' (for now)
3n - 9 = 69
3n = 69 + 9
3n = 78
n = 78/3
n = 26
Therefore, The number is 26
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Ugo [173]

Answer:

answer is

4ft * 5ft

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7 0
3 years ago
Figure A ~ Figure B<br> Find the volume of Figure A
postnew [5]

9514 1404 393

Answer:

  1 m³

Step-by-step explanation:

The ratio of volumes is the cube of the ratio of corresponding linear dimensions.

  Va/Vb = ((2 m)/(8 m))³ = (1/4)³ = 1/64

  Va = Vb(1/64) = (64 cu. m)/(64) = 1 cu. m

The volume of figure A is 1 m³.

4 0
3 years ago
Read 2 more answers
Police Chase: A speeder traveling 40 miles per hour (in a 25 mph zone) passes a stopped police car which immediately takes off a
zubka84 [21]

Answer:

a. 18.34 s b. 327.92 m

Step-by-step explanation:

a. How long before the police car catches the speeder who continued traveling at 40 miles/hour

The acceleration of the car a in 10 s from 0 to 55 mi/h is a = (v - u)/t where u = initial velocity = 0 m/s, v = final velocity = 55 mi/h = 55 × 1609 m/3600 s = 24.58 m/s and t = time = 10 s.

So, a =  (v - u)/t =  (24.58 m/s - 0 m/s)/10 s = 24.58 m/s ÷ 10 s = 2.458 m/s².

The distance moved by the police car in 10 s is gotten from

s = ut + 1/2at² where u = initial velocity of police car = 0 m/s, a = acceleration = 2.458 m/s² and t = time = 10 s.

s = 0 m/s × 10 s + 1/2 × 2.458 m/s² (10)²

s = 0 m + 1/2 × 2.458 m/s² × 100 s²

s = 122.9 m

The distance moved when the police car is driving at 55 mi/h is s' = 24.58 t where t = driving time after attaining 55 mi/h

The total distance moved by the police car is thus S = s + s' = 122.9 + 24.58t

The total distance moved by the speeder is S' = 40t' mi = (40 × 1609 m/3600 s)t' =  17.88t' m where t' = time taken for police to catch up with speeder.

Since both distances are the same,

S' = S

17.88t' = 122.9 + 24.58t

Also, the time  taken for the police car to catch up with the speeder, t' = time taken for car to accelerate to 55 mi/h + rest of time taken for police car to catch up with speed, t

t' = 10 + t

So, substituting t' into the equation, we have

17.88t' = 122.9 + 24.58t

17.88(10 + t) = 122.9 + 24.58t

178.8 + 17.88t = 122.9 + 24.58t

17.88t - 24.58t = 122.9 - 178.8

-6.7t = -55.9

t = -55.9/-6.7

t = 8.34 s

So, t' = 10 + t

t' = 10 + 8.34

t' = 18.34 s

So, it will take 18.34 s before the police car catches the speeder who continued traveling at 40 miles/hour

b. how far before the police car catches the speeder who continued traveling at 40 miles/hour

Since the distance moved by the police car also equals the distance moved by the speeder, how far the police car will move before he catches the speeder is given by S' = 17.88t' = 17.88 × 18.34 s = 327.92 m

4 0
2 years ago
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Levart [38]

Answer:

The price of a new computer is quantitative.

Step-by-step explanation:

A variable can be classified as qualitative or quantitative.

Qualitative:

When the possible values of the variables are labels, for example, good or bad, yes or no,...

Quantitative:

When the possible values of the variables are numbers, for example 1, 2, 1000,....

In this question:

The price of a computer is a numeric value, so it is a quantitative variable.

6 0
3 years ago
Ruth sees 11 flags in the park. Juno sees 4 more flags than Ruth. Sandra sees 9 more flags than Juno. How many flags does Sandra
Irina-Kira [14]
First you add 11+4 which equals 15 then you add 15+9 which equals 24. So Sandra sees 24 flags
7 0
3 years ago
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