Answer: Cell
Explanation: The cell is the most basic unit of life.
Cm3 into dm3 = 250/1000= 0.25dm3
Answer is in g convert mg into g = 125/1000= 0.125g
This means there is 0.125g of solids in 0.25dm3
Need to know how much is in 1dm3
0.25dm3 is 1/4 of 1dm3
0.125/4 = 0.03125
0.031g (2S.F)
Answer:
D. These elements have properties of both metals and nonmetals.
Explanation:
It can be concluded that the elements have properties of both metals and non-metals.
The elements that borders the ones described are both metals and non-metals. Most of these elements can be classified as metalloids.
On the periodic table, the elements around this region have properties of both metals and non-metals at certain temperature and pressure conditions.
Explanation:
The equilibrium constant of the reaction =
Initial concentration of HI = 0.311 M
After addition 0.174 mol of HI(g)
Concentration of HI added = ![\frac{0.174 mol}{1 L}=0.174 M](https://tex.z-dn.net/?f=%5Cfrac%7B0.174%20mol%7D%7B1%20L%7D%3D0.174%20M)
New concentration of HI = 0.311 M + 0.174 M = 0.485 M
![2HI\rightleftharpoons H_2+I_2](https://tex.z-dn.net/?f=2HI%5Crightleftharpoons%20H_2%2BI_2)
Initial concentration:
0.311 M
At equilibrium:
(0.485 M - x)
![K_{eq}=\frac{[H_2][I_2]}{[HI]^2}](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5BH_2%5D%5BI_2%5D%7D%7B%5BHI%5D%5E2%7D)
![1.80\times 10^{-2}=\frac{(4.71\times 10^{-2} M+x)\times (4.71\times 10^{-2} M+x)}{ (0.485 M-x)^2}](https://tex.z-dn.net/?f=1.80%5Ctimes%2010%5E%7B-2%7D%3D%5Cfrac%7B%284.71%5Ctimes%2010%5E%7B-2%7D%20M%2Bx%29%5Ctimes%20%284.71%5Ctimes%2010%5E%7B-2%7D%20M%2Bx%29%7D%7B%20%280.485%20M-x%29%5E2%7D)
![\sqrt{1.80\times 10^{-2}}=\frac{(4.71\times 10^{-2} M+x)}{ (0.485 M-x)}](https://tex.z-dn.net/?f=%5Csqrt%7B1.80%5Ctimes%2010%5E%7B-2%7D%7D%3D%5Cfrac%7B%284.71%5Ctimes%2010%5E%7B-2%7D%20M%2Bx%29%7D%7B%20%280.485%20M-x%29%7D)
![0.1342=\frac{(4.71\times 10^{-2} M+x)}{(0.485 M-x)}](https://tex.z-dn.net/?f=0.1342%3D%5Cfrac%7B%284.71%5Ctimes%2010%5E%7B-2%7D%20M%2Bx%29%7D%7B%280.485%20M-x%29%7D)
![0.065087 M-0.1342x=4.71\times 10^{-2} M+x](https://tex.z-dn.net/?f=0.065087%20M-0.1342x%3D4.71%5Ctimes%2010%5E%7B-2%7D%20M%2Bx)
![0.065087 M-4.71\times 10^{-2} M=1.1342x](https://tex.z-dn.net/?f=0.065087%20M-4.71%5Ctimes%2010%5E%7B-2%7D%20M%3D1.1342x)
![x=\frac{0.017987 M}{1.3142}=0.01586 M](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B0.017987%20M%7D%7B1.3142%7D%3D0.01586%20M)
Equilibrium concentrations:
![[HI]=0.485 M-x = 0.485 M - 0.01586 M= 0.46914 M](https://tex.z-dn.net/?f=%5BHI%5D%3D0.485%20M-x%20%3D%200.485%20M%20-%200.01586%20M%3D%200.46914%20M)
![[H_2]=[I_2]=4.71\times 10^{-2} M+x=4.71\times 10^{-2} M+0.01586 M](https://tex.z-dn.net/?f=%5BH_2%5D%3D%5BI_2%5D%3D4.71%5Ctimes%2010%5E%7B-2%7D%20M%2Bx%3D4.71%5Ctimes%2010%5E%7B-2%7D%20M%2B0.01586%20M)
![[H_2]=[I_2]=0.06296 M](https://tex.z-dn.net/?f=%5BH_2%5D%3D%5BI_2%5D%3D0.06296%20M)
Answer:
A) measuring mass of metal used in a reaction
Explanation:
Quantitive observations is data involving statistics and numerical values.