Answer:
Check explanation
Explanation:.
NOTE: kindly check for attached file/picture for the graph.
From the graph of absorbance against concentration from the question. We can see that the 0.3 mark absorbance is equivalent to 0.15 M. So, the concentration of CuSO4 is 0.15 M.
The concentration can also be calculated using the Beer-lambert equation for absorbance. The equation is given below;
A= ɛ×C×l --------------------------------------------------------------------------------------(1).
Where A= absorbance, ɛ= molar absorptivity, C= concentration and l= length.
Therefore, the concentration,C will now be; C= A/ ɛ×l. -------------------------------------------------------------------------(2).
Assuming the length,l is 1cm.
Hence, C= 0.300/ ɛ×1.
C= (0.300/ ɛ) M.
The volume of water vapour would be produced at 19°C and 780 torr is 548.5mL.
If 400 ml of CO2 is produced at 30°C at 740 torr, then number of moles can be calculated as:
By using ideal gas equation:
P1V1 = N1R1T1
P1 = pressure = 740torr
V1 = 400 ml = volume of CO2
R = Gas constant = 8.314
T = 273+30 = 303 k
740×400 = N1×8.314×303
N1 = (740×400) /(8.314×303) =117.5.
Chemical equation
C2H6 ---- 2CO2 + 3H2O.
As we noticed from the equation that
2 moles of CO2 = 3 moles of H2O
1 moles of CO2 × 1 moles of H2O
Then N2 = 117.5 moles of CO2 = 3/2 × 117.5 moles of H2O
By using ideal gas equation:
P2V2 = N2RT2
V2 = 3/2 × 117.5 × 8.314 × 292/ 780
= 548.5ml.
Thus, we found that the volume of water vapour would be produced at 19°C and 780 torr is 548.5mL.
learn more about ideal gas equation:
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Answer: Mg + 2HCl —> MgCl2 + H2
Explanation:
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