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zlopas [31]
2 years ago
11

Which is an example of making a quantitative observation?

Chemistry
1 answer:
Elanso [62]2 years ago
4 0

Answer:

A) measuring mass of metal used in a reaction

Explanation:

Quantitive observations is data involving statistics and numerical values.

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Which best describes the trends in electronegativity on the periodic table?
Wittaler [7]

Answer:

My bad i didnt mean to put that carry on.

Explanation:

7 0
3 years ago
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16. What is a pure substance formed when two or more different elementscombine called?A. compoundB. moleculeC. element
Lana71 [14]
<h2>Answer:</h2>

Compound. Option A is correct

<h2>Explanations:</h2>

When two or more different elements combines, a compound is formed. For instance, if carbon and oxygen combines, carbondioxide is formed according to the equation;

C+O_2\rightarrow CO_2

From the reaction, carbon and oxygen are the elements while carbondioxide is the compound. Hence we can conclude that a pure substance formed when two or more different elements combine called compound.

3 0
1 year ago
Behavioral therapy began with _______________.
Mrac [35]

Answer:

B

Explanation:

Behaviour therapy was popularized by the U.S. psychologist B.F. Skinner, who worked with mental patients in a Massachusetts state hospital.

3 0
2 years ago
Hydrogen iodide, HI, is formed in an equilibrium reaction when gaseous hydrogen and iodine gas are heated together. If 20.0 g of
Kaylis [27]

Answer: D. 19.9 g hydrogen remains.

Explanation:

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

a) moles of H_2

\text{Number of moles}=\frac{20.0g}{2g/mol}=10.0moles

b) moles of I_2

\text{Number of moles}=\frac{20.0g}{254g/mol}=0.0787moles

H_2(g)+I_2(g)\rightarrow 2HI(g)

According to stoichiometry :

1 mole of I_2 require 1 mole of H_2

Thus 0.0787 moles of l_2 require=\frac{1}{1}\times 0.0787=0.0787moles of H_2

Thus l_2 is the limiting reagent as it limits the formation of product and H_2 acts as the excess reagent. (10.0-0.0787)= 9.92 moles of H_2are left unreacted.

Mass of H_2=moles\times {\text {Molar mass}}=9.92moles\times 2.01g/mol=19.9g

Thus 19.9 g of H_2 remains unreacted.

5 0
2 years ago
Round the following number to 3 significant figures:<br><br> 15937<br><br> pls helpppp
Dmitry_Shevchenko [17]

Answer:

15900

Explanation:

I think hope this helps!! :D

6 0
3 years ago
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