The reaction rate is the speed at which products form, based on the rate of the slowest step in the mechanism.
Answer:
33.6 L
Explanation:
From the question given above, the following data were obtained from:
Initial volume (V1) = 8.40 L L
Initial pressure (P1) = P
Initial temperature (T1) = T
Final pressure (P2) = one-half the original pressure = ½P
Final temperature (T2) = double the original temperature = 2T
Final volume (V2) =.?
Thus, the new volume of the gas can be obtained as follow:
P1V1/ T1 = P2V2 /T2
P × 8.40 / T = ½P × V2 /2T
P × 8.40 / T = P × V2 / 4T
Cross multiply
T × P × V2 = P × 8.40 × 4T
Divide both side by T × P
V2 = (P × 8.40 × 4T) /T × P
V2 = 8.40 × 4
V2 = 33.6 L
Thus, the new volume of the gas is 33.6 L
18.is D
19.is A
hope it's correct
Im confused here. Add the rest of the question for me to help you
Taking into account the reaction stoichiometry, 340.0 moles of methane are produced when 85.1 moles of carbon dioxide gas react with excess hydrogen gas
<h3>Reaction stoichiometry</h3>
In first place, the balanced reaction is:
CO₂ + 4 H₄ → CH₄ + 2 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- CO₂: 1 mole
- H₄: 4 moles
- CH₄: 1 mole
- H₂O: 2 moles
<h3>Moles of CH₄ formed</h3>
The following rule of three can be applied: if by reaction stoichiometry 1 mole of CO₂ form 4 moles of CH₄, 85.1 moles of CO₂ form how many moles of CH₄?

<u><em>moles of CH₄= 340.4 moles</em></u>
Then, 340.0 moles of methane are produced when 85.1 moles of carbon dioxide gas react with excess hydrogen gas
Learn more about the reaction stoichiometry:
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