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saul85 [17]
2 years ago
5

Math problem need help

Mathematics
1 answer:
MrRa [10]2 years ago
8 0
Dang girl that’s really hard hope u get it
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Click on the solution set below until the correct one is displayed
kari74 [83]

Answer:

A. is ur answer

Step-by-step explanation:

Sorry if im wrong

5 0
2 years ago
the scale factor of the blueprint of a theater stage to the actual theater stage is 1in/6ft. the area of the stage on the blue p
liq [111]
Answer: 1728ft^2
The scale of the blueprint is <span>1in=6ft and the area of the stage is 48in^2. To convert the area, you just need to find the scale with inch^2. The equation would be:

</span>1 inch=6ft <span>
inch^2= x ft^2
(6ft)^2= x ft^2
36ft^2= x ft^2
x=36

1 inch^2 =36 ft^2
area of the actual stage= 48 inch^2 * (36 ft^2/inch^2)= 1728ft^2</span>
7 0
2 years ago
Will a 9/32 inch diameter pin fit into a reamed hole with a diameter of 0.278 inch? (Do not round off your answer and express it
ollegr [7]

Answer:

9/32 inch diameter pin will not fit into a reamed hole with a diameter of 0.278 inch

Step-by-step explanation:

Diameter of reamed hole = 0.278 inch

Radius of reamed hole = \frac{0.278}{2} =0.139

Surface area of reamed hole = \pi r^2

Surface area of reamed hole = 3.14 \times  (0.139)^2

Surface area of reamed hole = 0.06066794

Diameter of pin = \frac{9}{32}

Radius of pin =\frac{9}{64}

Surface area of pin = \pi r^2 = 3.14 \times ( \frac{9}{64})^2=0.0620

Since the surface area of pin is more than the surface area of hole .

So, a 9/32 inch diameter pin will not fit into a reamed hole with a diameter of 0.278 inch

7 0
3 years ago
What is 7 over 20 as a percentage
expeople1 [14]
7/20) * 100%
= 35%
= 0.3
4 0
2 years ago
Read 2 more answers
An organization has members who possess IQs in the top 4% of the population. If IQs are normally distributed, with a mean of 100
murzikaleks [220]

Answer:

The minimum IQ score will be "126".

Step-by-step explanation:

The given values are:

Mean

\mu = 100

Standard deviation

\sigma=15

Now,

⇒ P(z>x)=4 \ percent \ i.e., 0.04

⇒ P(z>\frac{x- \mu}{\sigma} )=0.04

⇒ 1-P(z \leq \frac{x-100}{15})=0.04

⇒ \frac{x-100}{15}=z0.96

            =NORMDIS(z=0.96)

            =1.751

⇒ x=100+15\times 1.751

      =126.265 \ i.e., 126

7 0
2 years ago
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