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crimeas [40]
3 years ago
7

An unfair coin with p(h) = 0.6 is flipped 3 times and the result of each toss is noted. what is the probability that there are a

t least two heads?

Mathematics
1 answer:
mr_godi [17]3 years ago
4 0
Total possible outcomes: (2)³=8 (heads or tails possibility on each toss) 

Draw out a Tree diagram to illustrate the given example, labelling the probability on each branch. 

Adding all the possible situations with P(t)≥2, we get 0.352 as the probability. 

Hope I helped :) 

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A=\cfrac{1}{4}(6)\cfrac{9^2}{2^2} \cot(30^o)\implies A=\cfrac{243}{8}\cot(30^o)\implies A=\cfrac{243\sqrt{3}}{8} \\\\[-0.35em] ~\dotfill\\\\ \textit{area of circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=\frac{4}{5} \end{cases}\implies A=\pi \left( \cfrac{4}{5} \right)^2\implies A=\cfrac{16\pi }{25} \\\\[-0.35em] ~\dotfill

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Step-by-step explanation:

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