First, the values of 2sqrt(3) or 3sqrt(3) are not even twice the length of the given base, 3.
Next, I would say that 6 is the better answer than 12, assuming that the triangle is”drawn-to-scale”.
Finally, I think the hypotenuse is 6.
Greater than because the line is dashed and the shaded region is in the positive or less negative numbers area. Greater than or equal would be the same but with a solid line.
Answer:
-14x+1
Step-by-step explanation:
-6x-8
-8x+9
-14x+1
Answer:
97.98
Step-by-step explanation:
The area of the parallelogram PQR is the magnitude of the cross product of any two adjacent sides. Using PQ and PS as the adjacent sides;
Area of the parallelogram = |PQ×PS|
PQ = Q-P and PS = S-P
Given P(0,0,0), Q(4,-5,3), R(4,-7,1), S(8,-12,4)
PQ = (4,-5,3) - (0,0,0)
PQ = (4,-5,3)
Also, PS = S-P
PS = (8,-12,4)-(0,0,0)
PS = (8,-12,4)
Taking the cross product of both vectors i.e PQ×PS
(4,5,-3)×(8,-12,4)
PQ×PS = (20-36)i - (16-(-24))j + (-48-40)k
PQ×PS = -16i - 40j -88k
|PQ×PS| = √(-16)²+(-40)²+(-88)²
|PQ×PS| = √256+1600+7744
|PQ×PS| = √9600
|PQ×PS| ≈ 97.98
Hence the area of the parallelogram is 97.98
56,105.61 is the answer rounded to the nearest hundred