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KIM [24]
3 years ago
13

Find the product of 3 1/8 and 12/7. Express your answer in simplest form

Mathematics
1 answer:
valina [46]3 years ago
3 0
3 1/8 • 12/7= 75/14 and simplified is 5 5/14 which should be your answer
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How many toothpicks would be needed for pattern 4
larisa86 [58]

can you show me what the math problem is?

7 0
2 years ago
<img src="https://tex.z-dn.net/?f=prove%20that%5C%20%20%5Ctextless%20%5C%20br%20%2F%5C%20%20%5Ctextgreater%20%5C%20%5Cfrac%20%7B
inysia [295]

\large \bigstar \frak{ } \large\underline{\sf{Solution-}}

Consider, LHS

\begin{gathered}\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } \\ \end{gathered}

We know,

\begin{gathered}\boxed{\sf{  \:\rm \: {sec}^{2}x - {tan}^{2}x = 1 \: \: }} \\ \end{gathered}  \\  \\  \text{So, using this identity, we get} \\  \\ \begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - ( {sec}^{2}\theta - {tan}^{2}\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}

We know,

\begin{gathered}\boxed{\sf{  \:\rm \: {x}^{2} - {y}^{2} = (x + y)(x - y) \: \: }} \\ \end{gathered}  \\

So, using this identity, we get

\begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - (sec\theta + tan\theta )(sec\theta - tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}

can be rewritten as

\begin{gathered}\rm\:=\:\dfrac {(\sec \theta + tan\theta ) - (sec\theta + tan\theta )(sec\theta -tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered} \\  \\  \\\begin{gathered}\rm \: = \:\dfrac {(\sec \theta + tan\theta ) \: \cancel{(1 - sec\theta + tan\theta )}} { \cancel{ \tan \theta - \sec \theta + 1} } \\ \end{gathered} \\  \\  \\\begin{gathered}\rm \: = \:sec\theta + tan\theta \\\end{gathered} \\  \\  \\\begin{gathered}\rm \: = \:\dfrac{1}{cos\theta } + \dfrac{sin\theta }{cos\theta } \\ \end{gathered} \\  \\  \\\begin{gathered}\rm \: = \:\dfrac{1 + sin\theta }{cos\theta } \\ \end{gathered}

<h2>Hence,</h2>

\begin{gathered} \\ \rm\implies \:\boxed{\sf{  \:\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } = \:\dfrac{1 + sin\theta }{cos\theta } \: \: }} \\ \\ \end{gathered}

\rule{190pt}{2pt}

5 0
2 years ago
What is the product of -2 1/4 and 4 1/2
solmaris [256]
The answer would be <span>-10.125</span>
5 0
3 years ago
Read 2 more answers
Which of the trigonometric ratios has a value that is undefined?
FinnZ [79.3K]

Answer:

\tan \left(\frac{\pi }{2}\right)

Step-by-step explanation:

We know that  tan(x) is defined as  sin(x)/cos(x):

\tan \left(\frac{\pi }{2}\right),\\\sin \left(\frac{\pi }{2}\right)=1,\\\cos \left(\frac{\pi }{2}\right)=0,\\\\

\tan \left(\frac{\pi }{2}\right) = 1/0 \\

1/0 is undefined as 0 is in the denominator

6 0
2 years ago
un solar tiene forma de 3/4 de círculo unido con un triángulo rectángulo , En este solar va a ser utilizado para sembrar clavele
Stolb23 [73]

Answer:

$1092671.191

Step-by-step explanation:

<u>Cálculo de Areas</u>

El área de un círculo de radio r se obtiene con la fórmula:

A_c=\pi r^2

El área de un triángulo de base b y altura h, perpendicular a la base es:

A_t=\frac{bh}{2}

Si el triángulo es rectángulo, b y h son los catetos

El solar tiene una forma tal como se ilustra en la figura anexa. Para averiguar el costo del abono y del techo, debe calcularse primero el área total a cultivar. Primero se determina el área de 3/4 de círculo de radio 5.9 metros

A_c=\frac{3}{4}\pi r^2

A_c=\frac{3}{4}\pi (5.9)^2

A_c=82.0191302\ m^2

Por su parte, el triángulo mostrado, tiene ambos catetos iguales al radio de círculo, por lo que su área será

A_t=\frac{r^2}{2}

A_t=\frac{(5.9)^2}{2}

A_t=17.405\ m^2

El área total del solar es la suma de ambas:

A_s=82.0191302\ m^2+17.405\ m^2

A_s=99.4241302\ m^2

El metro cuadrado de abono cuesta $8016. El costo de abono es

C_a=99.4241302\ m^2*8016=\$796983.8277

El metro cuadrado de techo cuesta $2974. El costo del techo es

C_t=99.4241302\ m^2*2974=\$295687.3632

El costo total es la suma de los dos anteriores:

Total=\$796983.8277+\$295687.3632

Total=\$1092671.191

El valor total a intervenir para la adecuación del solar es $1092671.191

7 0
3 years ago
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