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3 years ago

Rewrite 19/19 as a whole number

Mathematics

1 answer:

Elis [28]3 years ago

5 0

The answer is 1.

Because if you simplify (divide) 19/19 you get one.

4/4 would also be 1. Any number divided to itself will always be 1.

Whereas 30/15 would be 2 because thirty divided by fifteen is 2

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Step-by-step explanation:

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3 years ago

How do you do this problem? Simple and concise explanation please! TOP ANSWERERS!!!!

charle [14.2K]

Answer:

Just B and C

Step-by-step explanation:

Reduce this to the lowest amount possible.

log(3abc/6a^2b) = 2

=================

log(c/2a) = 2

c/2a = 10^2

c = 2a * 100

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This one is also correct.

=================

The rest are just incorrect.

There is only 1 answer that works and that is B.

C is close, but it is not correct.

D is backwards. B is the right way and D is the upside down of B.

E and F are just not the way to handle logs. Subtracting logs means division, not multiplication and not 1 log.

=================

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4 years ago

The mathematics section of a standardized college entrance exam had a mean of 19.8 and an SD of 5.1 for a recent year. Assume th

Fudgin [204]

Answer:

a) 0.84% of students scored over 32

b) 29.12% of students scored under 17

c) 70.04% of students scored between 17 and 32.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 19.8, \sigma = 5.1$

a) About what percent of students scored over 32?

This is 1 subtracted by the pvalue of Z when X = 32. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{32 - 19.8}{5.1}$

$Z = 2.39$

$Z = 2.39$ has a pvalue of 0.9916

1 - 0.9916 = 0.0084

So 0.84% of students scored over 32

b) About what percent of students scored under 17?

This is the pvalue of Z when X = 17. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{17 - 19.8}{5.1}$

$Z = -0.55$

$Z = -0.55$ has a pvalue of 0.2912

So 29.12% of students scored under 17

c) About what percent of students scored between 17 and 32?

This is the pvalue of Z when X = 32 subtracted by the pvalue of Z when X = 12. So

X = 32

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{32 - 19.8}{5.1}$

$Z = 2.39$

$Z = 2.39$ has a pvalue of 0.9916

X = 17

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{17 - 19.8}{5.1}$

$Z = -0.55$

$Z = -0.55$ has a pvalue of 0.2912

0.9916 - 0.2912 = 0.7004

70.04% of students scored between 17 and 32.

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3 years ago

The product of 4x and O is

Ilya [14]

Answer:

Always the product of any number and zero will be zero.

Step-by-step explanation:

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3 years ago

Read 2 more answers