Question

You have used the significant level of 0.01 to estimate the average hours of television viewing for the NJ students. What is the chance that our interval estimate does not contain the true population mean?A.99% B.10% C.100% D.1% E.None of the above

Answer 1

Answer:

1%

Step-by-step explanation:

Given : You have used the significant level of 0.01 to estimate the average hours of television viewing for the NJ students.

To Find :What is the chance that our interval estimate does not contain the true population mean?

Solution:

We are given that You have used the significant level of 0.01 to estimate the average hours of television viewing for the NJ students.

So, α=0.01

Significance level indicates a risk of concluding that a difference exists when there is no actual difference.

So, The chance that our interval estimate does not contain the true population mean is 0.01

So, The chance that our interval estimate does not contain the true population mean is $0.01 \times 100 = 1\%$

Hence Option D is true