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3 years ago

Calculate the value of (6.72 x 10^5) + (3.2 x 10^4)Give your answer in standard form.

Mathematics

1 answer:

madam [21]3 years ago

7 0

Answer:

7.04× 10^5

Step-by-step explanation:

6.72 x 10^5= 6.72 x 10^(4+1)= 6.72 x 10^1 ×10^4

= 67.2 x 10^4

(67.2 x 10^4)+ (3.2 x 10^4)

(67.2+3.2) × 10^4 = 70.4 × 10^4

7.04× 10^5

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Solve the following equation for y: 35x-7y=49

Brrunno [24]

The answer is Y equals -7+5x

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3 years ago

Read 2 more answers

Write the cosine ratio of angle b<br> and show work please

Dennis_Churaev [7]

The formula for cosine is adj/hyp. For angle B, 10 is the adjacent and 24 is the opposite. The hypotenuse ( in this case, 26) is the longest side. the ratio for angle b would be 10/26.

7 0

3 years ago

Persons taking a 30-hour review course to prepare for a standardized exam average a score of 620 on that exam. Persons taking a

Alina [70]

Given:

30-hour review course average a score of 620 on that exam.

70-hour review course average a score of 749.

To find:

The linear equation which fits this data, and use this equation to predict an average score for persons taking a 57-hour review course.

Solution:

Let x be the number of hours of review course and y be the average score on that exam.

30-hour review course average a score of 620 on that exam. So, the linear function passes through the point (30,620).

70-hour review course average a score of 749. So, the linear function passes through the point (70,749).

The linear function passes through the points (30,620) and (70,749). So, the linear equation is:

$y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)$

$y-620=\dfrac{749-620}{70-30}(x-30)$

$y-620=\dfrac{129}{40}(x-30)$

$y-620=\dfrac{129}{40}(x)-\dfrac{129}{40}(30)$

$y-620=\dfrac{129}{40}(x)-\dfrac{387}{4}$

Adding 620 on both sides, we get

$y=\dfrac{129}{40}x-\dfrac{387}{4}+620$

$y=\dfrac{129}{40}x+\dfrac{2480-387}{4}$

$y=\dfrac{129}{40}x+\dfrac{2093}{4}$

We need to find the y-value for $x=57$ .

$y=\dfrac{129}{40}(57)+\dfrac{2093}{4}$

$y=183.825+523.25$

$y=707.075$

$y\approx 707.1$

Therefore, the required linear equation for the given situation is $y=\dfrac{129}{40}x+\dfrac{2093}{4}$ and the average score for persons taking a 57-hour review course is 707.1.

4 0

3 years ago

Use the table to answer the question.

Over [174]

Answer:

in the survey, 16 out of 80 students who where asked favored chicken nuggets.

so we need to calculate like this:

530 * 16/80

=530 * 1/5

=530/5

=106

hope this helps your understanding, wish you good grades

3 0

3 years ago

Solve by substitution 3x+y=3 and 7x+2y=1

balu736 [363]

3x + y = 3

7x + 2y = 1

First isolate one of the variables (x or y) in one of the equations.

Isolate "y" in the first equation(because it is the easiest to isolate) and substitute it into the second equation.

3x + y = 3 Subtract 3x on both sides

3x - 3x + y = 3 - 3x

y = 3 - 3x

7x + 2y = 1

7x + 2(3 - 3x) = 1 [since y = 3 - 3x, you can substitute (3-3x) for "y"]

Multiply/distribute 2 into (3 - 3x)

7x + (3(2) - 3x(2)) = 1

7x + 6 - 6x = 1

x + 6 = 1 Subtract 6 on both sides

x = -5

Now that you know "x", substitute it into one of the equations (I will do both)

3x + y = 3

3(-5) + y = 3 [since x = -5, you can plug in -5 for "x"]

-15 + y = 3 Add 15 on both sides

y = 18

7x + 2y = 1

7(-5) + 2y = 1

-35 + 2y = 1 Add 35 on both sides

2y = 36 Divide 2 on both sides

y = 18

x = -5, y = 18 or (-5, 18)

5 0

3 years ago

Calculate the value of (6.72 x 10^5) + (3.2 x 10^4)Give your answer in standard form.​

Calculate the value of (6.72 x 10^5) + (3.2 x 10^4)Give your answer in standard form.