Answer:
The shelter can house 17 cats because
17 < 28.
Step-by-step explanation:
We cannot have fractions of cats, and we cannot have a negative number of cats. So the third statement is reasonable because c < 28.
The answer is “like” terms.
You add common terms together to get variables by themselves.
81÷s = 90÷100
s= 81 x 100 ÷ 90
s= 90
81 students is 90% of 90 students
If we try to evaluate this expression, we arrive at an indeterminate limit of the form ∞ · 0. So we rewrite this limit as
lim of [ e^(-x/5) / (1 / x^3) ] as x→∞
This results in an determinate form of 0/0, so we apply L'Hospital's rule by differentiating the numerator and denominator.
lim of [ -1/5e^(-x/5) / (-3/x^4) ] as x→∞
Multiply the numerator and denominator by x^4
lim of [ -1/5 * x^4 * e^(-x/5) / (-3) ] as x→∞
Since e^(-x/5) approaches 0 as x→∞, the limit evaluates to 0.
The answer to this question is 0.
Answer:
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