Answer:
one point
Step-by-step explanation:
A system of two linear equations will have one point in the solution set if the slopes of the lines are different.
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When the equations are written in the same form, the ratio of x-coefficient to y-coefficient is related to the slope. It will be different if there is one solution.
- ratio for first equation: 1/1 = 1
- ratio for second equation: 1/-1 = -1
These lines have <em>different slopes</em>, so there is one solution to the system of equations.
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<em>Additional comment</em>
When the equations are in slope-intercept form with the y-coefficient equal to 1, the x-coefficient is the slope.
y = mx +b . . . . . slope = m
When the equations are in standard form (as in this problem), the ratio of x- to y-coefficient is the opposite of the slope.
ax +by = c . . . . . slope = -a/b
As long as the equations are in the same form, the slopes can be compared by comparing the ratios of coefficients.
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If the slopes are the same, the lines may be either parallel (empty solution set) or coincident (infinite solution set). When the equations are in the same form with reduced coefficients, the lines will be coincident if they are the same equation.
X= 5 x= -9 y = -10 if this not the answer reverse it
This is incorrect. X can be negative, making the expression on the left less than 0. If x were -10, then:
3 x -10 + 1 > 0
-30 + 1 > 0
-29 > 0
Is NOT true.
Answer:
Step-by-step explanation:
<u><em>The complete question is</em></u>
A cone and a triangular pyramid have a height of 9.3 m and their cross-sectional areas are equal at every level parallel to their respective bases. The radius of the base of the cone is 3 in and the other leg (not x) of the triangle base of the triangular pyramid is 3.3 in
What is the height, x, of the triangle base of the pyramid? Round to the nearest tenth
The picture of the question in the attached figure
we know that
If their cross-sectional areas are equal at every level parallel to their respective bases and the height is the same, then their volumes are equal
Equate the volume of the cone and the volume of the triangular pyramid
![\frac{1}{3}\pi r^{2}H=\frac{1}{3}[\frac{1}{2}(b)(h)H]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D%5Cpi%20r%5E%7B2%7DH%3D%5Cfrac%7B1%7D%7B3%7D%5B%5Cfrac%7B1%7D%7B2%7D%28b%29%28h%29H%5D)
simplify
we have
substitute the given values
solve for x
