Well you need first 1 2/4 of a yard. Then you will need 5/6 of a yard. But first you need to put them together. So we need to find the common denominator. Six and four both share which multiple? Twelve. So let's rewrite that. You need 1 6/12 yards + 10/12 yards of wrapping paper. But before we do anything else we need to fix the mixed number. 1 6/12 isn't as easy to add ad 18/12 is. So 18/12 + 10/12 = 28/12
That can simplify as well. Now it's 14/6 which is equivalent to the fraction we had before. But it can also go down to 2 2/6. Now we can simplify it even further. By dividing it by two we can get 2 1/3. These are the measurements we need. So you would need how many thirds? Seven. (2 1/3 is seven thirds) This is your final answer.
You would need to have seven peices of wrapping paper cut to wrap both gift boxes.
Answer: D. took quiz :)
Step-by-step explanation:
Answer:
B. 34.90°
Step-by-step explanation:
✔️First, find GF using Trigonometric function:
Reference angle = 58°
Adjacent length = GF
Hypotenuse = 6 cm
Apply CAH, thus:
Cos 58 = Adj/Hyp
Cos 58 = GF/6
GF = 6*Cos 58
GF = 3.17951558 ≈ 3.18 cm
✔️Find angle K using the Sine Rule:
Substitute
Multiply both sides by 3.18
K = 34.8618741° ≈ 34.90°
Answer:
C.
Step-by-step explanation:
W = 1.414213562 (or 2 squared)
x = 2 (because the y gets cancelled out in the first equation)
y = 1 (since 2(1)=2(1))
tell me if i’m right :)
