Answer:
A task time of 177.125s qualify individuals for such training.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by
After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.
In this problem, we have that:
A distribution that can be approximated by a normal distribution with a mean value of 145 sec and a standard deviation of 25 sec, so 
.
The fastest 10% are to be given advanced training. What task times qualify individuals for such training?
This is the value of X when Z has a pvalue of 0.90.
Z has a pvalue of 0.90 when it is between 1.28 and 1.29. So we want to find X when 
.
So
A task time of 177.125s qualify individuals for such training.
Step-by-step explanation:
from what I can see there are 2 options to make the 2 triangles congruent :
either the opposite sides must be equal or the neighboring sides must be equal.
so, either
5x = 3x + 10
and
5x - 2 = 4x + 3
or
5x = 4x + 3
and
5x - 2 = 3x + 10
for the first
5x = 3x + 10
2x = 10
x = 5
control
5x - 2 = 4w + 3
5×5 - 2 = 4×5 + 3
23 = 23
correct.
for the second
5x = 4x + 3
x = 3
control
5×3 - 2 = 3×3 + 10
15 - 2 = 9 + 10
13 = 19
no, not a valid solution.
so, x = 5
Answer:
Options (1), (2), (3) and (4)
Step-by-step explanation:
By applying the sine and cosine rules in the given triangle,
sinθ = 
cosθ = 
cos(30°) = 
= 
= 
sin(30°) = 
= 
= 
cos(60°) =
=
=
sin(60°) = =
=
=
Options (1), (2), (3) and (4) are the correct options.
Answer:
A=254.34
Step-by-step explanation:
1. A=πr²
2. A=π(9)²
3. A=π(81)
4. A=3.14(81)
5. A=254.34
Divide number of guitars by 100% and multiply into discount given
149/100 x 29
1.49 x 29
43.21
$43.21 had been removed
Therefore $105.79 is the guitar cost after discount
Hope it was useful ☻
