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3 years ago

What’s 3.1 divieded by 27.9

Mathematics

2 answers:

Andrei [34K]3 years ago

8 0

Answer: 0.111111111111111

Step-by-step explanation:

Y_Kistochka [10]3 years ago

4 0

Answer: 0.1111111111111…

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What is the value of the expression below.4/5+3/5+3.5×5

Solnce55 [7]

Answer:

18.9

Step-by-step explanation:

4/5 + 3/5 + 3.5 * 5

Well using PEMDAS you would need to do 3.5 x 5 which is 17.5

After that you would to 4/5 + 3/5 which is 7/5 also as 1 2/5

Then you would do 7/5 + 17.5 = 18.9

I might be wrong but that is what I got and I hope it helps you :)

6 0

3 years ago

Veronica bought 2.1 pounds of turkey at the deli. The price of the turkey was 2.87 per pound. She also bought 4.8 pounds of ham.

Brrunno [24]

Answer:

Choose the correct answer from your choices.

Step-by-step explanation:

First, we find the price of the turkey by multiplying the weight of turkey by the price per pound.

2.1 pounds of turkey at the deli. The price of the turkey was 2.87 per pound.

2.1 lb * 2.87 $/lb = $6.03

Then, we find the price of the ham by multiplying the weight of ham by the price per pound.

She also bought 4.8 pounds of ham. The price of the ham was 2.11 per pound.

4.8 lb * 2.11 $/lb = $10.13

Now we add the two prices together.

$6.03 + $10.13 = $16.16

The total price was $16.16

6 0

3 years ago

A line, y = mx + b, passes through the point (1, 6) and is parallel to

koban [17]

Answer: b=6

Step-by-step explanation:

6 is in the y intercept place so it equals 6

8 0

3 years ago

Three cards are drawn from a standard deck of 52 cards without replacement. Find the probability that the first card is an ace,

MrRissso [65]

Answer:

$4.82\cdot 10^{-4}$

Step-by-step explanation:

In a deck of cart, we have:

a = 4 (aces)

t = 4 (three)

j = 4 (jacks)

And the total number of cards in the deck is

n = 52

So, the probability of drawing an ace as first cart is:

$p(a)=\frac{a}{n}=\frac{4}{52}=\frac{1}{13}=0.0769$

At the second drawing, the ace is not replaced within the deck. So the number of cards left in the deck is

$n-1=51$

Therefore, the probability of drawing a three at the 2nd draw is

$p(t)=\frac{t}{n-1}=\frac{4}{51}=0.0784$

Then, at the third draw, the previous 2 cards are not replaced, so there are now

$n-2=50$

cards in the deck. So, the probability of drawing a jack is

$p(j)=\frac{j}{n-2}=\frac{4}{50}=0.08$

Therefore, the total probability of drawing an ace, a three and then a jack is:

$p(atj)=p(a)\cdot p(j) \cdot p(t)=0.0769\cdot 0.0784 \cdot 0.08 =4.82\cdot 10^{-4}$

4 0

3 years ago

For the point P(17.-9) and Q(24. - 4), find the distance d{P.Q) and the coordinates of the midpoint M of the

Elza [17]

Answer:

im pretty sure this is the answer :) ym = (y1 + y2)/2

Step-by-step explanation:

7 0

3 years ago