Write the quotient and the remainder for the following (x²-10x+24)÷(x+6)solve and answer plz

Mathematics

1 answer:

elena-s [515]3 years ago

7 0

Answer:

On dividing, we found that the quotient is (x-4) and the remainder is equal to 0.

Step-by-step explanation:

We need to find the quotient and the remainder for the following (x²-10x+24)÷(x+6).

The numerator is (x²-10x+24) and the denominator is (x+6). It can be written as :

$\dfrac{x^2-10x+24}{x+6}=\dfrac{(x-4)(x-6)}{(x+6)}\\\\=(x-4)$

On dividing, we found that the quotient is (x-4) and the remainder is equal to 0.

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Answer:

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c = $6\sqrt{2}$

Step-by-step explanation:

Since the triangles are right triangles with 60 and 45 degree angles, their side lengths follow special triangles.

A 45-45-90 right triangle has side lengths $1-1-\sqrt{2}$ .

A 30-60-90 right triangle has side lengths $1 - \sqrt{3} -2$ .

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