1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vodka [1.7K]
2 years ago
13

Write the quotient and the remainder for the following (x²-10x+24)÷(x+6)solve and answer plz ​

Mathematics
1 answer:
elena-s [515]2 years ago
7 0

Answer:

On dividing, we found that the quotient is (x-4) and the remainder is equal to 0.

Step-by-step explanation:

We need to find the quotient and the remainder for the following (x²-10x+24)÷(x+6).

The numerator is (x²-10x+24) and the denominator is (x+6). It can be written as :

\dfrac{x^2-10x+24}{x+6}=\dfrac{(x-4)(x-6)}{(x+6)}\\\\=(x-4)

On dividing, we found that the quotient is (x-4) and the remainder is equal to 0.

You might be interested in
What is the value of n? n–2=10n+4/2 n =
slamgirl [31]

simplify


n-2 = 10n/2 + 4/2


n-2 = 5n + 2


subtract 5n to both sides


n - 2 - 5n = 5n + 2 - 5n


simplify


-4n - 2 = 2


add 2 to both sides


-4n - 2 + 2 = 2 + 2


simplify


-4n = 4


divide both sides by -4


-4n/-4 = 4/-4


simplify


n = -1




                             hope it helps



8 0
3 years ago
Easy but need help :(((
adelina 88 [10]
A function cannot be a function if any x is repeating. The x in A has the number 1 repeating. The x is C has 2 repeating the x in D has 1 repeating.
Therefore, our answer would be (B)
7 0
3 years ago
Read 2 more answers
I need help with this ​
LuckyWell [14K]

Answer:

1st - Yes ; 2nd - Yes ; 3rd - Yes ; 4th - No

Step-by-step explanation:

8 0
3 years ago
The life of a red bulb used in a traffic signal can be modeled using an exponential distribution with an average life of 24 mont
BartSMP [9]

Answer:

See steps below

Step-by-step explanation:

Let X be the random variable that measures the lifespan of a bulb.

If the random variable X is exponentially distributed and X has an average value of 24 month, then its probability density function is

\bf f(x)=\frac{1}{24}e^{-x/24}\;(x\geq 0)

and its cumulative distribution function (CDF) is

\bf P(X\leq t)=\int_{0}^{t} f(x)dx=1-e^{-t/24}

• What is probability that the red bulb will need to be replaced at the first inspection?

The probability that the bulb fails the first year is

\bf P(X\leq 12)=1-e^{-12/24}=1-e^{-0.5}=0.39347

• If the bulb is in good condition at the end of 18 months, what is the probability that the bulb will be in good condition at the end of 24 months?

Let A and B be the events,

A = “The bulb will last at least 24 months”

B = “The bulb will last at least 18 months”

We want to find P(A | B).

By definition P(A | B) = P(A∩B)P(B)

but B⊂A, so  A∩B = B and  

\bf P(A | B) = P(B)P(B) = (P(B))^2

We have  

\bf P(B)=P(X>18)=1-P(X\leq 18)=1-(1-e^{-18/24})=e^{-3/4}=0.47237

hence,

\bf P(A | B)=(P(B))^2=(0.47237)^2=0.22313

• If the signal has six red bulbs, what is the probability that at least one of them needs replacement at the first inspection? Assume distribution of lifetime of each bulb is independent

If the distribution of lifetime of each bulb is independent, then we have here a binomial distribution of six trials with probability of “success” (one bulb needs replacement at the first inspection) p = 0.39347

Now the probability that exactly k bulbs need replacement is

\bf \binom{6}{k}(0.39347)^k(1-0.39347)^{6-k}

<em>Probability that at least one of them needs replacement at the first inspection = 1- probability that none of them needs replacement at the first inspection. </em>

This means that,

<em>Probability that at least one of them needs replacement at the first inspection =  </em>

\bf 1-\binom{6}{0}(0.39347)^0(1-0.39347)^{6}=1-(0.60653)^6=0.95021

5 0
3 years ago
A cookie jar contains 6 chocolate chip cookies, 4 oatmeal cookies, 8 peanut butter cookies, and 2 sugar cookies. If a cookie is
Tpy6a [65]
You have 20 cookies total in the jar.  The probability of choosing an oatmeal is 4/20, and the probability of choosing a peanut butter cookie is 8/20.  In order to find the probability of pulling a peanut butter cookie OR an oatmeal cookie, we have to add the probabilities together.  8/20 + 4/20 = 12/20 or 6/10 or 3/5.  The answer is C.
7 0
3 years ago
Other questions:
  • Consider the right triangle. A right triangles with side lengths 28 meters and 45 meters. The hypotenuse is unknown. What is the
    10·2 answers
  • What is the difference of 5.9-2.2
    15·1 answer
  • Brody and Amanda can you for one hour and 20 minutes before serving to fish at 1:50 PM at what time did they start canoeing
    13·2 answers
  • identify a two-digit dividend that will result in a quotient with a remainder of 1 when the divisor is 4.
    11·2 answers
  • The end points of wx are w (-5,-1) and x (2,6) What is the length of wx
    12·1 answer
  • Whats does x equal for 2(x+6)&lt;3x+8
    14·1 answer
  • Round 7.49 to the nearest tenth <br>​
    5·1 answer
  • Why does the expression i to the power 4n+2 is always equal to -1​
    6·1 answer
  • Halp me children it's important​
    8·2 answers
  • How many cubes are colored on one side when there are 729 cubes that form a 9 x 9 x9 cube
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!