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vodka [1.7K]
2 years ago
13

Write the quotient and the remainder for the following (x²-10x+24)÷(x+6)solve and answer plz ​

Mathematics
1 answer:
elena-s [515]2 years ago
7 0

Answer:

On dividing, we found that the quotient is (x-4) and the remainder is equal to 0.

Step-by-step explanation:

We need to find the quotient and the remainder for the following (x²-10x+24)÷(x+6).

The numerator is (x²-10x+24) and the denominator is (x+6). It can be written as :

\dfrac{x^2-10x+24}{x+6}=\dfrac{(x-4)(x-6)}{(x+6)}\\\\=(x-4)

On dividing, we found that the quotient is (x-4) and the remainder is equal to 0.

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Andrew pays a monthly membership fee of $10 at his gym. Each time he uses the gym, he pays $5. Last month, Andrew spent a total
Ivenika [448]

Answer:

11

Step-by-step explanation:

If we input 11 into the equation, we get: 10 + 5(11) = 65.

5 x 11 = 55

55 + 10 = 65

Therefore x = 11

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2 years ago
What is the slope of (-3,-6) and (4,7)​
Gelneren [198K]

Answer:

13/7

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(7-(-6))/(4-(-3))

m=(7+6)/(4+3)

m=13/7

3 0
3 years ago
Solve for x: 24x + 12 = 16
vfiekz [6]

Answer:

x=1/6 or x=0.1666666667

Step-by-step explanation:

5 0
2 years ago
The cost of a skateboard c after a 15% discount can be represented by the expression c−0.15c . Simplify the expression.
ohaa [14]

Answer:

0.85c

Step-by-step explanation:

To simplify the expression, subtract like terms:

c - 0.15c

= 0.85c

So, the simplified expression is 0.85c

5 0
2 years ago
Read 2 more answers
On a coordinate plane, triangle A B C is shown. Point A is at (0, 0), point B is at (3, 4), and point C is at (3, 2). What is th
Elena L [17]

Answer:

The area of triangle for the given coordinates is  1.5\sqrt{4.6}

Step-by-step explanation:

Given coordinates of triangles as

A = (0,0)

B = (3,4)

C = (3,2)

So, The measure of length AB = a = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Or, a = \sqrt{(3-0)^{2}+(4-0)^{2}}

Or, a =  \sqrt{9+16}

Or, a =   \sqrt{25}

∴ a = 5 unit

Similarly

The measure of length BC = b = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Or, b = \sqrt{(3-3)^{2}+(2-4)^{2}}

Or, a =  \sqrt{0+4}

Or, b =   \sqrt{4}

∴ b = 2 unit

And

So, The measure of length CA = c = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Or, c = \sqrt{(3-0)^{2}+(2-0)^{2}}

Or, c =  \sqrt{9+4}

Or, c =   \sqrt{13}

∴ c = \sqrt{13} unit

Now, area of Triangle written as , from Heron's formula

A = \sqrt{s\times (s-a)\times (s-b)\times (s-c)}

and s = \frac{a+b+c}{2}

I.e  s = \frac{5+2+\sqrt{13}}{2}

Or. s =  \frac{7+\sqrt{13}}{2}

So, A = \sqrt{(\frac{(7+\sqrt{13})}{2})\times ((\frac{(7+\sqrt{13})}{2})-5)\times (\frac{7+\sqrt{13}}{2}-2)\times (\frac{7+\sqrt{13}}{2}-\sqrt{13})}

Or, A = \sqrt{(\frac{(7+\sqrt{13})}{2})\times (\frac{(\sqrt{13}-3)}{2})\times (\frac{4+\sqrt{13}}{2})\times (\frac{7-\sqrt{13}}{2})}

Or, A = \frac{3}{2} × \sqrt{1+\sqrt{13} }

∴  Area of triangle = 1.5\sqrt{4.6}

Hence The area of triangle for the given coordinates is  1.5\sqrt{4.6}  Answer

7 0
3 years ago
Read 2 more answers
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