Answer:
False
Step-by-step explanation:
We first write the equation in the form ax² + bx + c=0 which gives us:
3x² - 6x + 9=0
Given the quadratic formula,
x= [-b ±√(b²- 4ac)]/2a ,the discriminant proves whether the equation has real roots or not.
The discriminant, which is the value under the root sign, may either be positive, negative or zero.
Positive discriminant- the equation has two real roots
Negative discriminant- the equation has no real roots
Zero discriminant - The equation has two repeated roots.
In the provided equation, b²-4ac results into:
(-6)²- (4×3×9)
=36-108
= -72
The result is negative therefore the equation has no real solutions.
F(-3) would be -8, because you would use the first equation. f(2) would be 4 apparently cause theres no x after the 4, or in the equation of the 4. Hope this helps. Please rate, leave a thanks, and mark a brainliest answer(not necessarily mine). Thanks, it really helps! :D
<span>The graph of g(x) is the graph of f(x)translated 3 units up.</span>
Step-by-step explanation:
5/8 × 6/8= 30/8 => this is the wrong one
it should be 5/8 × 6/8= 30/64.
9/10×3/10= 27/100 => this is the true one
1) 180-(44+45)=91
2) 180-(53+37)=180-90=90
