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Molodets [167]
3 years ago
6

26 - 2(10 - 1) + (3 + 4 \times 11)" alt="26 - 2(10 - 1) + (3 + 4 \times 11)" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
goldfiish [28.3K]3 years ago
5 0

26-2\left(10-1\right)+\left(3+4\cdot 11\right)

26-(2)(9)+3+(4)(11)

26-18+3+(4)(11)

8+3+(4)(11)

8+3+44

8+47

55

"55 is correct answer".

Hope this helps!

Thanks!

-Charlie

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Find f. f ″(x) = x^−2, x > 0, f(1) = 0, f(6) = 0
marin [14]

If you do in fact mean f(1)=f(6)=0 (as opposed to one of these being the derivative of f at some point), then integrating twice gives

f''(x) = -\dfrac1{x^2}

f'(x) = \displaystyle -\int \frac{dx}{x^2} = \frac1x + C_1

f(x) = \displaystyle \int \left(\frac1x + C_1\right) \, dx = \ln|x| + C_1x + C_2

From the initial conditions, we find

f(1) = \ln|1| + C_1 + C_2 = 0 \implies C_1 + C_2 = 0

f(6) = \ln|6| + 6C_1 + C_2 = 0 \implies 6C_1 + C_2 = -\ln(6)

Eliminating C_2, we get

(C_1 + C_2) - (6C_1 + C_2) = 0 - (-\ln(6))

-5C_1 = \ln(6)

C_1 = -\dfrac{\ln(6)}5 = -\ln\left(\sqrt[5]{6}\right) \implies C_2 = \ln\left(\sqrt[5]{6}\right)

Then

\boxed{f(x) = \ln|x| - \ln\left(\sqrt[5]{6}\right)\,x + \ln\left(\sqrt[5]{6}\right)}

3 0
2 years ago
Help me classify the triangles by its sides and measuring its angles :)
Anni [7]

Answer:

1. isosceles

2. Right

Step-by-step explanation:

Here, we want to give the kind of triangle in each of the diagrams

1. From what we can see, we have two sides equal to each other using the given markings. More specifically, the base sides are equal and that makes the triangle an isosceles triangle

2. From what we can see here, we have an angle of 90 degrees on one of the sides of the triangle. In other words, we have a right angle on one of the sides.

This makes the triangle, a right triangle

7 0
3 years ago
4. In this figure, B↔A↔
LenaWriter [7]

Answer:

B. 25 degrees

Step-by-step explanation:

i think

6 0
3 years ago
I’m stuck can some one help me
abruzzese [7]

Answer:

3) Midpoint is (-4,0.5)

Option A is correct.

4) Midpoint is (2.5,0)

Option B is correct.

5) The factors are (x+4)(x-7)

Option C is correct.

6) The factors are (x+4)(x+2)

Option A is correct.

Step-by-step explanation:

Question 3

Find midpoint of the following:

(2,-7), (-10,8)

The formula used to find midpoint is: Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )

We have x_1=2, y_1=-7, x_2=-10,y_2=8

Putting values and finding midpoint

Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )\\Midpoint=(\frac{2-10}{2},\frac{-7+8}{2} )\\Midpoint=(\frac{-8}{2},\frac{1}{2} )\\Midpoint=(-4,0.5 )

So, Midpoint is (-4,0.5)

Option A is correct.

Question 4

Find midpoint of the following:

(2,-10), (3,10)

The formula used to find midpoint is: Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )

We have x_1=2, y_1=-10, x_2=3,y_2=10

Putting values and finding midpoint

Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )\\Midpoint=(\frac{2+3}{2},\frac{-10+10}{2} )\\Midpoint=(\frac{5}{2},\frac{0}{2} )\\Midpoint=(2.5,0 )

So, Midpoint is (2.5,0)

Option B is correct.

Question 5

Factor each completely

x^2-3x-28

We will break the middle term and find factors

x^2-3x-28\\=x^2-7x+4x-28\\Taking\:common\\=x(x-7)+4(x-7)\\=(x+4)(x-7)

So, the factors are (x+4)(x-7)

Option C is correct.

Question 6

Factor each completely

x^2+6x+8

We will break the middle term and find factors

x^2+6x+8\\=x^2+4x+2x+8\\=x(x+4)+2(x+4)\\=(x+4)(x+2)

So, the factors are (x+4)(x+2)

Option A is correct.

7 0
3 years ago
(b) Melissa bought 18 pounds of flour for $10.
abruzzese [7]

Answer:

$1.80 per pound.

Step-by-step explanation:

You take 18/10 =1.80.

Hope that helps!

7 0
3 years ago
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