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Molodets [167]
3 years ago
6

26 - 2(10 - 1) + (3 + 4 \times 11)" alt="26 - 2(10 - 1) + (3 + 4 \times 11)" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
goldfiish [28.3K]3 years ago
5 0

26-2\left(10-1\right)+\left(3+4\cdot 11\right)

26-(2)(9)+3+(4)(11)

26-18+3+(4)(11)

8+3+(4)(11)

8+3+44

8+47

55

"55 is correct answer".

Hope this helps!

Thanks!

-Charlie

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In a carnival​ game, the player selects a ball one at a​ time, without​ replacement, from an urn containing twotwo purplepurple
dezoksy [38]
<span>The urn contains 2 purple balls and 4 white balls. The player pay $4 for start the game and get $1.5 for every ball drawn until one purple ball is drawn. The maximal revenue would be $7.5 when 4 white balls and 1 purple balls are drawn.
If the purple ball is p and white ball is w, t</span>he possible sample space of drawings are {p, wp, wwp, wwwp, wwwwp}

<span>1. Write down the probability distribution for the player earning

The player earning </span>for each event depends on the number of balls drawn subtracted the ticket price.<span>
p= 2/6
The player earnings would be: 1*$1.5 -$4= - $2.5
wp= (4*2)/(6*5) = 4/15
</span>The player earnings would be: 2*1.5- $4= - $1
wwp= (4*3*2)/(6*5*4)= 1/5
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wwwwp= (4*3*2*2*1)/(6*5*4*3*2*1) = 1/15
The player earnings would be: 5*$1.5 -$4=  $3.5

2. Find its expected value

The expected value would be:
chance of event * earning 
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Total expected value= (1/3 * - 2.5)+ (4/15*-1) + (1/5*0.5) + (2/15 *2) + ( 1/15 *3.5)= 
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This game basically a rip off.
6 0
3 years ago
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