3 years ago

Christian is 3 times as old as marie. marie is 12 years old. how old is christian

Mathematics

1 answer:

skad [1K]3 years ago

8 0

Christian is 36 years old.

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A taxi fare is $3 and then $0.40 for every kilometre. A taxi fare is $9 . How far has the taxi travelled?

Charra [1.4K]

Answer:

y = 3 + 0.40x

Step-by-step explanation:

Fixed cost of taxi fare = $3

Additional cost = $0.40

Let

y = Total cost

x = number of kilometers

The equation:

Total cost = Fixed cost of taxi fare + (Additional cost * number of kilometers)

y = 3 + 0.40x

8 0

3 years ago

Please assist me on this question please

Flauer [41]

Answer:

12 units

Step-by-step explanation:

x is to 16 as 9 is to x

x/16 = 9/x cross multiply

x^2 = 144

x =12

6 0

1 year ago

Which best describes the graphs of the line that passes through (−12, 15) and (4, −5), and the line that passes through (−8, −9)

konstantin123 [22]

Answer:

C) They are perpendicular lines.

Step-by-step explanation:

We first need to find the slope of the graph of the lines passing through these points using:

$m = \frac{y_2-y_1}{x_2-x_1}$

The slope of the line that passes through (−12, 15) and (4, −5) is

$m_{1} = \frac{ - 5 - 15}{4 - - 12}$

$m_{1} = \frac{ - 20}{16} = - \frac{5}{4}$

The slope of the line going through (−8, −9) and (16, 21) is

$m_{2} = \frac{21 - - 9}{16 - - 8}$

$m_{2} = \frac{21 + 9}{16 + 8}$

$m_{2} = \frac{30}{24} = \frac{5}{4}$

The product of the two slopes is

$m_{1} \times m_{2} = - \frac{4}{5} \times \frac{5}{4} = - 1$

Since

$m_{1} \times m_{2} = - 1$

the two lines are perpendicular.

4 0

3 years ago

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A bottle of nail Polish holds 0.8 ounce, A bottle of perfume holds 0.45. How many more of nail Polish hold?

Tasya [4]

The nail polish hold 0.35 more ounces than the perfume bottle

8 0

3 years ago

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I need help with Which table shows the correct methods used to justify the solution steps?

12345 [234]

Answer:

x = 8

Step-by-step explanation:

3 (x - 5) + 7x = 65

3x - 15 + 7x = 65

10x - 15 = 65

10x = 80

x = 8

5 0

2 years ago

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