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Serhud [2]
3 years ago
15

Line k has a slope of 2/3. If line m is parallel to line k, then it has a slope of

Mathematics
1 answer:
dalvyx [7]3 years ago
5 0
<span>If line m is parallel to line k, then it has a slope of C)2/3</span>
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Solve the expressions on the left when x=5<br>3x-10<br>x^2-15<br>5x-21<br>x+10-8​
Nitella [24]

Answer:

5

10

4

7

Step-by-step explanation:

Apply the value of x into the expressions:

3(5) - 10 = 15 - 10

           = 5

5² - 15 = 25 - 15

          = 10

5(5) - 21 = 25 - 21

             = 4

5 + 10 - 8 = 15 - 8

               = 7

5 0
3 years ago
Read 2 more answers
Work your brain this evening y'all!! I had $3.00. My Mom gave me $10.00. My Dad Gave me $30.00. My Aunt &amp; Uncle gave me $100
liraira [26]

Answer:

150 i think

Step-by-step explanation:

4 0
3 years ago
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A person wants to grow potatoes in his backyard. His backyard plot is 60ft by 60 ft and he can plant 2 potatoes for every square
Fantom [35]

Answer:

1800 potatoes

Step-by-step explanation:

60ft x 60ft = 3600 square feet

3600/2=1800

8 0
3 years ago
One of the tallest buildings in a country is topped by a high antenna. The angle of elevation from the position of a surveyor on
irina1246 [14]

Answer:

a. distance of the surveyor to the base of the building = 2051.90 ft

b. height of the building = 1384 ft

c. Angle of elevation from the surveyor to the top of the antenna = 38.31°

d. Height of antenna  =  237.08 ft

Step-by-step explanation:

​The picture above is a illustration of the described event.

a = the height of the flag

b = the height of the building

c = distance of the surveyor from the base of the building

the angle of elevation from the position of the surveyor on the ground to the top of the building = 34°  

distance from her position to the top of the building  = 2475 ft

distance from her position to the top of the flag  = 2615 ft

​(a) How far away from the base of the building is the surveyor​ located?​

using the SOHCAHTOA principle

cos 34° = c/2475

c =  0.8290375726  × 2475

c = 2051.8679921

c = 2051.90 ft

(b) How tall is the​ building

The height of the building = b

sin 34° = opposite /hypotenuse

0.5591929035 = b/2475

b =  0.5591929035  × 2475

b =  1384.0024361

b =  1384.00 ft

​(c) What is the angle of elevation from the surveyor to the top of the​ antenna?

let the angle = ∅

cos ∅ = adjacent/hypotenuse

cos ∅ = 2051.90/2615

cos ∅ =  0.784665392

∅ = cos-1  0.784665392

∅ =   38.310258303

∅ =  38.31°

​(d) How tall is the​ antenna?

height of the antenna = a

sin 38.31° = opposite/hypotenuse

sin 38.31° = (a + b)/2615

sin 38.31° × 2615 = (a + b)

(a + b) =  0.6199159917  × 2615

(a + b) =  1621.0803182

(a + b) = 1621. 08 ft

Height of antenna = 1621. 08 - 1384.00  =  237.08031822 ft

Height of antenna  =  237.08 ft

8 0
3 years ago
If f(x)=|x+7|, find f(−12).<br><br><br> −19<br><br><br> −5<br><br><br> 5<br><br><br> 19
Slav-nsk [51]

Answer:

5

Step-by-step explanation:

insert f(-12) for f(x) and solve

f(-12)=|-12+7|

add -12 and 7

f(-12)=|-5|

absolute value makes it positive

f(-12)=5

6 0
3 years ago
Read 2 more answers
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