How is this solved please help anyone

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Dmitrij [34]

White her is white b

7 0

3 years ago

Read 2 more answers

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Anettt [7]

Answer:

Choice C: approximately 121 green beans will be 13 centimeters or shorter.

Step-by-step explanation:

What's the probability that a green bean from this sale is shorter than 13 centimeters?

Let the length of a green bean be $X$ centimeters.

$X$ follows a normal distribution with

mean $\mu = 11.2$ and
standard deviation $\sigma = 2.1$ .

In other words,

$X\sim \text{N}(11.2, 2.1^{2})$ ,

and the probability in question is $X \le 13$ .

Z-score table approach:

Find the z-score of this measurement:

$\displaystyle z= \frac{x-\mu}{\sigma} = \frac{13-11.2}{2.1} = 0.857143$ . Closest to 0.86.

Look up the z-score in a table. Keep in mind that entries on a typical z-score table gives the probability of the left tail, which is the chance that $Z$ will be less than or equal to the z-score in question. (In case the question is asking for the probability that $Z$ is greater than the z-score, subtract the value from table from 1.)

$P(X\le 13) = P(Z \le 0.857143) \approx 0.8051$ .

"Technology" Approach

Depending on the manufacturer, the steps generally include:

Locate the cumulative probability function (cdf) for normal distributions.
Enter the lower and upper bound. The lower bound shall be a very negative number such as $-10^{9}$ . For the upper bound, enter $13$
Enter the mean and standard deviation (or variance if required).
Evaluate.

For example, on a Texas Instruments TI-84, evaluating $\text{normalcdf})(-1\text{E}99,\;13,\;11.2,\;2.1 )$ gives $0.804317$ .

As a result,

$P(X\le 13) = 0.804317$ .

Number of green beans that are shorter than 13 centimeters:

Assume that the length of green beans for sale are independent of each other. The probability that each green bean is shorter than 13 centimeters is constant. As a result, the number of green beans out of 150 that are shorter than 13 centimeters follow a binomial distribution.

Number of trials $n$ : 150.
Probability of success $p$ : 0.804317.

Let $Y$ be the number of green beans out of this 150 that are shorter than 13 centimeters. $Y\sim\text{B}(150,0.804317)$ .

The expected value of a binomial random variable is the product of the number of trials and the probability of success on each trial. In other words,

$E(Y) = n\cdot p = 150 \times 0.804317 = 120.648\approx 121$

The expected number of green beans out of this 150 that are shorter than 13 centimeters will thus be approximately 121.

7 0

3 years ago

Please help I really need help

katrin2010 [14]

Answer:

No

Step-by-step explanation:

Use the vertical line test, you can conclude that this is not a function.

5 0

2 years ago

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Hannah and Anthony are siblings who have ages that are consecutive odd integers. The sum of their ages is 92. Which equations co

Wewaii [24]

Answer:

h = Hannah's age

h - 2 = Anthony's age

Hannah is 47, Anthony is 45

Step-by-step explanation:

Using one variable and an expression with the same variable, you can find the sum of the siblings ages:

h = Hannah's age

h - 2 = Anthony's age

h + (h - 2) = 92

Combine like terms: 2h - 2 = 92

Add '2' to both sides: 2h - 2 + 2 = 92 + 2 or 2h = 94

Divide by 2: 2h/2 = 94/2

Solve for h: h = 47 years old (Hannah)

h - 2 = 45 years old (Anthony)

6 0

3 years ago

Find the product with the exponent in simplest form. Then, identify the values of x and y. 1 1 X 63.64 = 6 Y X = y =

Snezhnost [94]

Answer:

x = 7 y = 12

Step-by-step explanation:

4 0

2 years ago