Answer:
Step-by-step explanation:
Step 1: Obtain zero on one side and then factor. Step 2: Set each factor equal to zero. Step 3: Solve each of the resulting equations. This technique requires the zero factor property to work so make sure the quadratic is set equal to zero before factoring in step 1.
Part 1: If the roots of a polynomial are a, b, and c, then the factors can be written in the form (x - a), (x - b), and (x - c). In this case, we have (x - 3), (x - [3 + i]), and (x - [3 - i]). The three factors are (x - 3)(x - 3 - i)(x - 3 + i).
Part 2: The two factors with complex terms are (x - 3 - i)(x - 3 + i), and multiplying these terms as a difference of two squares can give:
(x - 3)^2 - i^2 = x^2 - 6x + 9 - (-1) = x^2 - 6x + 10
Part 3: We now multiply (x^2 - 6x + 10) by the remaining factor of (x - 3). This results in the cubic expression:
(x^2 - 6x + 10)(x - 3)
= x^3 - 3x^2 - 6x^2 + 18x + 10x - 30
= x^3 - 9x^2 + 28x - 30
Answer:
-2
I think it's -2 because you're dividing x by 2 so you'd divide -4 by 2.
Answer:
the answer is -8
Step-by-step explanation:
x<=-8
the answer is -8
