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aleksandr82 [10.1K]
3 years ago
9

HELP! this is for geometry, i really need help on number 13 but if you can help me with the others.

Mathematics
1 answer:
Zina [86]3 years ago
4 0
1 ray DE
2 ray ED
3 ray EC
4 ray CE
5 ray DC
6 ray CD
7 ray CA
8 ray AC
9 ray CB
10 ray BC
11 ray AB
12 ray BA
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The function f(x) is defined as f(x) = One-third(6)x. Which table of values could be used to graph g(x), a reflection of f(x) ac
a_sh-v [17]

The table of values that could be used to graph g(x), a reflection of f(x) across the x-axis is table (c)

<h3>How to determine the table of values?</h3>

From the question, we have the following equation that can be used in our computation:

f(x) = One-third(6)x

When this statement is represented as an equation, we have the following representation

f(x)= 1/3(6)ˣ

The transformation is given as

A reflection of f(x) across the x-axis

This means that

g(x) = -f(x)

So, we have

g(x) = -1/3(6)ˣ

What this means is that the values of f(x) are negated to get g(x)

The table that represents this is table (c)

Hence, the table of values is table (c)

Read more about transformation at

brainly.com/question/27224272

#SPJ1

3 0
1 year ago
The ratio of red fish to yellow fish in the pond is 2:3. If there are 24 yellow fish, how many red fish are in the pond?
alexira [117]

Answer:

16

Step-by-step explanation:

Since there are 24 yellow fish and the ratio of the yellow fish to the red fish is 3:2. Then we know that 24/3=8. This means that 1 is equal to 8 fish. Since there are 2 ones for the red fish, we times 8 by 2 to get 16.

5 0
3 years ago
(2x^2+7x-4)+(-10x-4)​
arsen [322]

Answer:

2x^{2} -3x-8

Step-by-step explanation:

Combine like terms: \\7x+(-10x)=-3x\\-4+(-4)= -8 \\Write in standard form:\\2x^{2} -3x-8

3 0
3 years ago
woody's cafe real estate tax of $1,110.85 was due November 1, 2013. Due to financial problems, Woody was unable to pay his cafe'
slega [8]
8 1/4=0.0825 or 8.25%

a). $1,110.85 * 8.25%= $91.65

b). $1110.85 + $91.65= $1,202.50
7 0
3 years ago
Read 2 more answers
2 points) Test each of the following series for convergence by the Integral Test. If the Integral Test can be applied to the ser
alexgriva [62]

Answer:

Required result : (a) Divergent. (b) Convergent. (c) Divergent, (d) Not exists. (e) Not exists.

Step-by-step explanation:

By the definition of integral test the series for a integer n and a continuous function f(x) which is monotonic decreasing in [n,\infty) then the infinite series \sum_{n}^{\infty} converges or diverges if and only if the improper integral \int_{n}^{\infty} converges or diverges.

Given,

(a) \sum_{n=1}^{\infty}9^n(\ln(9^n))^n

=5(\ln(9))^5\sum_{n=1}^{\infty}9^nn^5\hfill (1)

Then,

\int_{1}^{\infty}9^n(\ln(9^n))^5

=5(\ln 9)^5\int_{1}^{\infty}9^nn^5dn\hfill (2)

Let,

I=\int 9^nn^9

By using integral calculator we get,

I=\dfrac{\left(2\ln\left(3\right)n\left(\ln\left(3\right)n\left(\ln\left(3\right)n\left(\ln\left(3\right)n\left(2\ln\left(3\right)n-5\right)+10\right)-15\right)+15\right)-15\right)\mathrm{e}^{2\ln\left(3\right)n}}{8\ln^6\left(3\right)}

which is divergent. Therefore given (2) is divergent and so is (1).

(b) \sum_{n=1}^{\infty}ne^{-8n}\hfill (3)

Then in integral form,

\int_{1}^{\infty}ne^{-8n}

=\frac{9e^{-8}}{64}

=4.72\times 10^{-5}

Thus given series (3) is convergent.

(c) \sum_{n=1}^{\infty}ne^{8n}\hfill (4)

Then in integral form,

\int_{1}^{\infty}ne^{-8n}

Now let,

I=\int n e^{-8n}

Applying integral calculator we get,

I=\dfrac{\left(8n-1\right)\mathrm{e}^{8n}}{64}

which is divergent and thus,

\int_{1}^{\infty}I is divergent. So, given series (4) is divergent.

(d) \sun_{n=1}^{\infty}ln(3n)^n

which is in integral form,

\int_{1}^{\infty}\ln (3n)^n

during integration since there is no any antiderivative, the result could not be found.

(e)  \sum_{n=1}^{\infty}n+7(-4)^n

Integral form is,

\int_{1}^{\infty}n+7^{(-4)^n}

Let,

I=\int _{1}^{b}n+7^{(-4)^n}

Using integral calculator we get,

I=\frac{1}{2\ln(-4)}\Big[\ln(-4)b^2-2\Gamma(0,-\ln(7)(-4)^b)+2\Gamma(0,4\ln(7))-\ln(-4)\Big]

But,

\lim_{b\to \infty}I not exists.

4 0
3 years ago
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