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wlad13 [49]
3 years ago
5

(p2+3p+6)+(2p2+6p+6) Please get this right. AND DON'T SPAM!

Mathematics
1 answer:
gayaneshka [121]3 years ago
6 0

(p² + 3p + 6) + (2p² + 6p + 6)

First you must combine (aka sum) like terms. Like terms are numbers that have matching variables OR are numbers with out variables OR have matching variables with matching exponents. In this case the like terms are p² and 2p² (they both have the exponent p that is squared); 3p and 6p (they both have the variable p attached); and 6 and 6 (both numbers without variables)

(p² + 2p²) + (3p + 6p) + (6 + 6)

3p² + 9p + 12

Hope this helped!

~Just a girl in love with Shawn Mendes

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What is 10 to the fourth power simplified as
Marrrta [24]

Answer:

10000

Step-by-step explanation:

Multiply 10 times each time by 4. Make it easier just by adding 4 zeros.

6 0
3 years ago
if a line crosses the y-axis at (0, 1) and has a slope of `4/5`, what is the equation of the line? A. 4y − 5x = 5 B. y − 4x = 5
slamgirl [31]

Answer:

option (d) is correct.

if a line crosses the y-axis at (0, 1) and has a slope of \frac{4}{5}, then equation  of line is 5y - 4x = 5.

Step-by-step explanation:

Given : if a line crosses the y-axis at (0, 1) and has a slope of \frac{4}{5}.

We need to find the equation of line.

Equation of line is of the form y = mx + c, where m is the slope of line and c is the y- intercept. that is the point where line meets y- axis.

Given y intercept at (0, 1 ) ⇒ c = 1

Also, slope m = \frac{4}{5}

Substitute it in equation,  we get ,

y = mx + c ⇒  y=\frac{4}{5}x+1

Solving , we get equation of line as ,

5y = 4x + 5 ⇒ 5y - 4x = 5

Thus, option (d) is correct.

if a line crosses the y-axis at (0, 1) and has a slope of \frac{4}{5}, then equation  of line is 5y - 4x = 5.

5 0
3 years ago
Read 2 more answers
Match each exponential function to its percent rate of change.
vredina [299]
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2. Answer: 4% decay 
f(x)= a(b)^{x}
f(x)= 104(0.96)²
Then the value of the variable would be:
a= 104
b=0.96
Since b is <1 then the function would decay. The rate of change percent would be: (.96 * 100%) - 100%= 96%-100%= -4%. The function rate of change is 4% decay 

3. Answer: 40% decay 
f(x)= a(b)^{x}
f(x)= 74(0.6)²
Then the value of the variable would be:
a= 74
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f(x)= 44(1.4)²
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a= 44
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Since b is >1 then the function would grow. The rate of change percent would be: (1.40 * 100%) - 100%= 140%-100%= 40%. The function rate of change is 40% growth

5. Answer: 14% decay
f(x)= a(b)^{x}
f(x)= 40(0.86)²
Then the value of the variable would be:
a= 40
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Since b is <1 then the function would decay. The rate of change percent would be: (0.86 * 100%) - 100%= 86%-100%= -14%. The function rate of change is 14% decay

6. Answer: 14% growth
f(x)= a(b)^{x}
f(x)= 8(1.14)²
Then the value of the variable would be:
a= 8
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Since b is >1 then the function would grow. The rate of change percent would be: (1.14 * 100%) - 100%= 114%-100%= 14%. The function rate of change is 14% growth
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mixas84 [53]
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