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3 years ago

(p2+3p+6)+(2p2+6p+6) Please get this right. AND DON'T SPAM!

Mathematics

1 answer:

gayaneshka [121]3 years ago

6 0

(p² + 3p + 6) + (2p² + 6p + 6)

First you must combine (aka sum) like terms. Like terms are numbers that have matching variables OR are numbers with out variables OR have matching variables with matching exponents. In this case the like terms are p² and 2p² (they both have the exponent p that is squared); 3p and 6p (they both have the variable p attached); and 6 and 6 (both numbers without variables)

(p² + 2p²) + (3p + 6p) + (6 + 6)

3p² + 9p + 12

Hope this helped!

~Just a girl in love with Shawn Mendes

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Find the area of the circle.

Alona [7]

Answer:

C is the answer.

Step-by-step explanation:

Area of circle = $\pi r^2$

radius = 3

use pi = 3.14

So you have 3.14(3)^2

which equals 28.26 units squared, which is C.

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What is the area of the circle shown? Use 3.14 to approximate pi. Round your answer to the nearest hundredth.

leva [86]

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2 years ago

A paper describes a study in which researchers observed wait times in coffee shops in Boston. Both wait time and gender of the c

kvasek [131]

Answer:

$t=\frac{85.8-113.4}{\sqrt{\frac{(50)^2}{145}+\frac{(75)^2}{141}}}}=-3.65$

$p_v =2*P(t_{(284)}$

Using Excel we can use the following code: "=2*T.DIST(-3.65;284;TRUE)"

So the p value is a very low value and using any significance level giveen $\alpha=0.05$ always $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and there is enough evidence to conclude that the means are different.

Step-by-step explanation:

1) Data given and notation

$\bar X_{M}=85.8$ represent the mean for the males

$\bar X_{F}=113.4$ represent the mean for females

$s_{M}=50$ represent the sample standard deviation for males

$s_{F}=75$ represent the sample standard deviation for female

$n_{M}=145$ sample size for the group poisoned

$n_{F}=141$ sample size for the group unpoisoned

t would represent the statistic (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to check if the mean for the two groups are equal or not , the system of hypothesis would be:

Null hypothesis: $\mu_{M} = \mu_{F}$

Alternative hypothesis: $\mu_{M} \neq \mu_{F}$

If we analyze the size for the samples both are higher than 30 but the population deviations are not given, so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{\bar X_{M}-\bar X_{F}}{\sqrt{\frac{s^2_{M}}{n_{M}}+\frac{s^2_{F}}{n_{F}}}}$ (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

3) Calculate the statistic

We can replace in formula (1) the results obtained like this:

$t=\frac{85.8-113.4}{\sqrt{\frac{(50)^2}{145}+\frac{(75)^2}{141}}}}=-3.65$

4) Statistical decision

The first step is calculate the degrees of freedom, on this case:

$df=n_{M}+n_{F}-2=145+141-2=284$

Since is a two tailed test the p value would be:

$p_v =2*P(t_{(284)}$

Using Excel we can use the following code: "=2*T.DIST(-3.65;284;TRUE)"

4 0

3 years ago

4C2 + 6C + 3C2 - 2C - 3

Gnesinka [82]

4c2+6c-3c2-2c-3

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "c2" was replaced by "c^2". 1 more similar replacement(s).

Step by step solution :Step 1 :
Equation at the end of step 1 : ((((4•(c2))+6c)-3c2)-2c)-3 Step 2 :Equation at the end of step 2 : (((22c2 + 6c) - 3c2) - 2c) - 3 Step 3 :Trying to factor by splitting the middle term

3.1 Factoring c2+4c-3

The first term is, c2 its coefficient is 1 .
The middle term is, +4c its coefficient is 4 .
The last term, "the constant", is -3 

Step-1 : Multiply the coefficient of the first term by the constant 1 • -3 = -3

Step-2 : Find two factors of -3 whose sum equals the coefficient of the middle term, which is 4 .

-3 + 1 = -2 -1 + 3 = 2
Final result : c2 + 4c - 3

3 0

3 years ago