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Fiesta28 [93]
3 years ago
6

Please help numbers 2-20 evens only

Mathematics
2 answers:
miv72 [106K]3 years ago
7 0

Answer:  x=9,y=-1/3

Step-by-step explanation: This is for Q. 16

Rearrange terms to line up properly.

x-3y=10

x+3y=8

eliminate y terms

x=10

x=8   now add all like terms, remember it's a given that there's a one in

         front of a variable.

2x=18 solve for x

x=9 now plug in the nine into one of the original eq.s and solve for y

9+3y=8

3y=-1

y=-1/3  always check solutions in both eq.s to vertify. they both work    

           

Marina86 [1]3 years ago
3 0

Answer:

Q6: x= 10, y = -11

Q8: x= -3; y= 8

Q10: k= 7; j= -1

Step-by-step explanation:

Question6.

2x + y = 9..............1

-2x - 3y = 13...............2

Let's eliminate x by adding equation 1 and 2.

-2y = 22

y = 22/-2

y = -11

Substitute y = -11 in equation 1.

2x + y = 9

2x + (-11) = 9

2x - 11 = 9

2x = 9 + 11

2x = 20

x = 20/2

x = 10

x =10; y= -11

Question 8.

x + 2y = 13.............(I)

x + 6y = 45......…....(2)

By elimination method, let's take off x by subtracting equation 1 from 2.

6y - 2y = 45 - 13

4y = 32

y = 8.

Substitute y = 8 in equation 1.

x + 2y = 13

x + 2(8) = 13

x + 16 = 13

x = 13 - 16

x = -3

y= 8; x = -3

Question 10:

2j + 3k = 19 ..............1

2j + 7k = 47...............2

Let's eliminate j by subtracting equation 1 from equation 2.

4k = 28

k = 28/4

k= 7

Substitute k = 7 in equation 1.

2j + 3k = 19

2j + 3(7) = 19

2j + 21 = 19

2j = 19 - 21

2j = -2

j= -1

k= 7; j = -1

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