Answer:
152.7 yd
Step-by-step explanation:
I presume that there is a fence around the perimeter and separating the various plots.
AG = BF = CE = 18 yd
GH = DE = 12 yd
EO² = DE² + DO²
1 5² = 12² + DO²
225 = 144 + DO²
81 = DO²
DO = 9
BC = DO = EF = 9 yd
AC = DH = EG = 17 yd
AO² = AB² + BO² = 8² + 6² = 64 + 36 =100
AO = √100 = 10 yd
CO² = BC² + BO² = 9² + 6² = 81 + 36 = 127
CO = √127 yd
GO² = FG² + FO² = 8² + 12² =64 + 144 = 208
GO = √208 = 4√13 yd
Fencing needed
= (AC + DH + EG) + (AG + BF + CE) + AO + CO + EO + GO
= (3 × 17) + 3 × 18) + 10 + √127 + 15 + 4√13
= 51 + 54 + 25 + 11.27 + 14.42
= 152.7 yd
