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vfiekz [6]
3 years ago
6

Find the value of X such that the data set has the given mean. 99, 123, 105, 114, 107, X; mean 108

Mathematics
2 answers:
Ulleksa [173]3 years ago
8 0

Answer:

The value of x is 100

Step-by-step explanation:

* Lets revise how to find the missing number of the given Mean

- Add up the numbers you know.

- Set up your equation by adding the sum of the numbers plus “x”

- Divide the sum by the number of numbers given.

- Equate them by the value of the mean

- Solving for "x"

- Check the Answer

* Now lets solve the problem

- The numbers are 99 , 123 , 105 , 114 , 107

- The sum of the numbers = 99 + 123 + 105 + 114 + 107 = 548

- The equation is ⇒ (548 + x)/6 = 108 ⇒ × 6 both sides

∴ 548 + x = 648 ⇒ subtract 548 from both sides

∴ x = 100

* Now lets check the answer

- The mean = (99 + 123 + 105 + 114 + 107 + 100)/6 = 648/6 = 108

∴ The answer x = 100 is correct

* The value of x is 100

sladkih [1.3K]3 years ago
5 0

Answer:

The value of X = 100

Step-by-step explanation:

<u>Points to remember </u>

Mean of a data set is given by,

Mean = (sum of data)/number of data

<u>To find the value of X</u>

It is given a data set,99, 123, 105, 114, 107, X

Sum of data set = 99 + 123 + 105 + 114 + 107 + X =  548 + X

Mean = 108

Mean =  (sum of data)/number of data

108 = (548 + X)/6

548 + X = 108 * 6 = 648

X = 648 - 548 = 100

Therefore the value of X = 100

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  • \cos x=\frac{\sqrt2}2=\frac1{\sqrt2} when x=\pm\frac\pi4;
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\cos x is continuous over its domain, so the intermediate value theorem tells us that

\cos x\ge\frac{\sqrt2}2

is true for -\frac\pi4\le x\le\frac\pi4.

For all x, we take into account that \cos x is 2\pi-periodic, so the above inequality can be expanded to

-\dfrac\pi4\le x+2n\pi\le\dfrac\pi4

where n is any integer. Equivalently,

-\dfrac\pi4-2n\pi\le x\le\dfrac\pi4-2n\pi

To get the corresponding solution set for

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\implies\boxed{-\dfrac{7\pi}{12}-2n\pi\le x\le-\dfrac\pi{12}-2n\pi}

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