Answer:
<em>The uniform rate of depreciation is $56,333 per year, or 11% per year.</em>
Step-by-step explanation:
<u>Rate of Depreciation</u>
If some object has a certain value P and after some time t its value decreases to Q, the rate of depreciation is a measure of how much its value changed per unit time.
It can be calculated as:
It can also be expressed as a percentage, dividing the previous value by P.
The school bus reduces its value from $512,000 to $343,000 in 3 years, thus:
R = 56,333 $/year
Expressed as a percentage:
R = 56,333 / 512,000 = 0.11
R = 11%/year
The uniform rate of depreciation is $56,333 per year, or 11% per year.
Hey!
Hope this helps...
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x + y = 3
x = 3 - y
y = 2x - 15
y = 2(3 - y) - 15
y = 6 - 2y - 15
y = -2y - 9
3y = -9
y = -3
y = 2x - 15
-3 = 2x - 15
-2x = -12
x = 6
So...
The answer is: (6, -3)
Problem 4
Answer: 47
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Work Shown:
f(x) = x^2 - 7x + 3
f(x) = (x)^2 - 7(x) + 3
f(-4) = (-4)^2 - 7(-4) + 3 ... replace each x with -4
f(-4) = 16 - 7(-4) + 3
f(-4) = 16 + 28 + 3
f(-4) = 44 + 3
f(-4) = 47
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Problem 5
Answer: See the attached image for the table
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Work Shown:
Plug in n = 27 and we get...
C = 26 + 10*n
C = 26 + 10*27
C = 26 + 270
C = 296
The input n = 27 leads to the output C = 296. This means that 27 people will have the cost be $296
Do the same for n = 39
C = 26 + 10*n
C = 26 + 10*39
C = 26 + 390
C = 416
The input n = 39 leads to the output C = 416. This means that 39 people will have the cost be $416
and also n = 43 as well
C = 26 + 10*n
C = 26 + 10*43
C = 26 + 430
C = 456
The input n = 43 leads to the output C = 456. This means that 43 people will have the cost be $456
I have no idea what you're talking about. Can you explain in detail plz?
