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3 years ago

Jose paid 45.00$ for 5 movie tickets . EACH ticket cost the same amount . What was the cost of each movie ticket in dollars ?

Mathematics

2 answers:

MA_775_DIABLO [31]3 years ago

5 0

Answer:

Step-by-step explanation:

divide 45 and 5, you get 9

gulaghasi [49]3 years ago

4 0

Answer:

45.00$ divided by 5.00$ is 9.00$

i hoped this helped!

Step-by-step explanation:

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What does "w" equal in the equation w²+6w-112+0?

Elenna [48]

Answer:

w^2+6w-112

Step-by-step explanation:

combine like terms

w^2 and 6w are not like terms

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3 years ago

Two farmers had a truck. The first farmer paid 4/5 of thr price, in the second paid the rest of his Farmer's share was 9600 what

alex41 [277]

9600 x 5 = 48000
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3 years ago

The probability density function of the time you arrive at a terminal (in minutes after 8:00 A.M.) is f(x) = 0.1 exp(−0.1x) for

Blababa [14]

$f_X(x)=\begin{cases}0.1e^{-0.1x}&\text{for }x>0\\0&\text{otherwise}\end{cases}$

a. 9:00 AM is the 60 minute mark:

$f_X(60)=0.1e^{-0.1\cdot60}\approx0.000248$

b. 8:15 and 8:30 AM are the 15 and 30 minute marks, respectively. The probability of arriving at some point between them is

$\displaystyle\int_{15}^{30}f_X(x)\,\mathrm dx\approx0.173$

c. The probability of arriving on any given day before 8:40 AM (the 40 minute mark) is

$\displaystyle\int_0^{40}f_X(x)\,\mathrm dx\approx0.982$

The probability of doing so for at least 2 of 5 days is

$\displaystyle\sum_{n=2}^5\binom5n(0.982)^n(1-0.982)^{5-n}\approx1$

i.e. you're virtually guaranteed to arrive within the first 40 minutes at least twice.

d. Integrate the PDF to obtain the CDF:

$F_X(x)=\displaystyle\int_{-\infty}^xf_X(t)\,\mathrm dt=\begin{cases}0&\text{for }x$

Then the desired probability is

$F_X(30)-F_X(15)\approx0.950-0.777=0.173$

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3 years ago

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gizmo_the_mogwai [7]

Answer:

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Step-by-step explanation:

its easy not even needed to be explained!!

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gavmur [86]

Answer:

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Step-by-step explanation:

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