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Brilliant_brown [7]
3 years ago
11

H(n)=-2n(2)+4; Find h(4)

Mathematics
1 answer:
anygoal [31]3 years ago
8 0

Answer:

h(4) = –12

Step-by-step explanation:

⇒ What the question is asking is that when the function h(n) = –2n(2) + 4 is h(4), what will the function repond to when solving for h(4)? So, solve for the function h(4):

h(4) = –2n(2) + 4

⇒ Since n was replaced with 4 in the function h(4), substitute any n for 4 into the function:

h(4) = –2(4)(2) + 4

⇒ Simplify:

h(4) = –16 + 4

⇒ Solve:

h(4) = –12

<u>Answer:</u> h(4) = –12

<em>I hope you understand and that this helps with your question! </em>:)

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Answer:

We can find the square by multiplying the binomial by itself. However terms Lastly, we see that the first sign of the trinomial is the same as the sign of the binomial. For the middle term of the trinomial, double the product of the two terms.

Step-by-step explanation:

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3 years ago
The number of phone calls that Actuary Ben receives each day has a Poisson distribution with mean 0.1 during each weekday and me
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Answer:

There is a 0.73% probability that Ben receives a total of 2 phone calls in a week.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

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The problem states that:

The number of phone calls that Actuary Ben receives each day has a Poisson distribution with mean 0.1 during each weekday and mean 0.2 each day during the weekend.

To find the mean during the time interval, we have to find the weighed mean of calls he receives per day.

There are 5 weekdays, with a mean of 0.1 calls per day.

The weekend is 2 days long, with a mean of 0.2 calls per day.

So:

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P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

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There is a 0.73% probability that Ben receives a total of 2 phone calls in a week.

3 0
3 years ago
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