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grandymaker [24]
3 years ago
14

PLEASE HELP I GIVE THANKS

Mathematics
1 answer:
Arada [10]3 years ago
8 0
M5 is 58 degrees because the angle next to m1 is 58
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Table 1 contains outputs of the function f(x)=b^x for some x values and Tables 2 contains outputs of the function g(x)=logb (x)
REY [17]
What’s your question
6 0
2 years ago
A number is equal to three times the smaller number also the sum of the smaller number and four is the larger number situation i
emmainna [20.7K]

Answer:

this question is missing needed information

8 0
2 years ago
Admission for a movie is $8 for children and $12 for adults. On a certain day, 3200 people attend the movie theater and $33,040
Nezavi [6.7K]
Let us assume the number of children attending the movie = x
Let us also assume the number of adults attending the movie = y
Cost of admission for a children in the movie = $8
Cost of admission of an adult in the movie = $12
Number of people going to the movie on a certain day = 3200
Total amount collected from the movie theater = $33040
Then
x + y = 3200
And
8x + 12y = 33040
2x + 3y = 8260
Let us first take the equation
x + y = 3200
x = 3200 - y
Now we will put the value of x in the equation
2x + 3y = 8260
2(3200 - y) + 3y = 8260
6400 - 2y + 3y = 8260
y = 8260 - 6400
   = 1860
Now we will put the value of y from the above deduction in the equation
x + y = 3200
x + 1860 = 3200
x = 3200 - 1860
   = 1340
So the number of children going to the movie theater is 1340 and the number of adults going to the movie theater is 1860.
5 0
3 years ago
How do I do this???!????
Marina CMI [18]
Can you resubmit your question so that I can give you a reasonable answer
4 0
3 years ago
On day two of a study on body temperatures, 106 temperatures were taken. Suppose that we only have the first 10 temperatures to
NemiM [27]

Answer:

The 95% confidence interval for the mean of all body temperatures is between 97.76 ºF and 99.12 ºF

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 10 - 1 = 9

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 9 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 2.2622

The margin of error is:

M = T*s = 2.2622*0.3 = 0.68

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 98.44 - 0.68 = 97.76 ºF

The upper end of the interval is the sample mean added to M. So it is 98.44 + 0.68 = 99.12 ºF

The 95% confidence interval for the mean of all body temperatures is between 97.76 ºF and 99.12 ºF

4 0
2 years ago
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