In order for us to tell whichever fraction is greater than or lesser than, we need to look for the missing part.
For example, we have 2/3 and 1/3.
2/3 needs to have 1/3 in order to complete the whole.
1/3 needs to have 2/3 in order to complete the whole.
1/3 < 2/3
<span>So 2/3 is bigger than 1//3</span>
Answer:
7x^2y(2x-3y)
Step-by-step explanation:
Factor 7x^2y out of 14x^3y-21x^2y^2
I think you have to solve like each section like (5x3+3)2 first solve that and then solve the middle one and then the last one and I think they all have to be equal to each other , and if they aren’t then her anwser isn’t correct
Using the properties of operations the given pair of expressions are not equivalent
<u>Solution:</u>
Given that, we have to use the properties of operations to determine if each pair of expressions is equivalent
<em><u>And the two expressions are:</u></em>
Now, we know that, there are four (4) basic properties of operations:
<em>Commutative, Associative, Distributive and Identity. These properties only apply to the operations of addition and multiplication.</em>
So, if we observe we can apply distributive property on 1st expression
The distributive property of multiplication states that when a number is multiplied by the sum of two numbers, the first number can be distributed to both of those numbers and multiplied by each of them separately, then adding the two products together for the same result as multiplying the first number by the sum.
Here the resulting expression is 2 – x and it is not equivalent to 2 – 2x
Hence, the given two expressions are not equal.
The two number are 39 and 13
<em><u>Solution:</u></em>
Let the two numbers be "a" and "b"
Let the larger number be "a" and the smaller number be "b"
<em><u>Given that, sum of two numbers is 52</u></em>
a + b = 52 ---------- eqn 1
<em><u>One number is 3 times as large as the other number</u></em>
Larger number = 3 times smaller number
a = 3b -------- eqn 2
<em><u>Let us solve eqn 1and eqn 2</u></em>
<em><u>Substitute eqn 2 in eqn 1</u></em>
3b + b = 52
4b = 52
b = 13
<em><u>Substitute b = 13 in eqn 2</u></em>
a = 3(13)
a = 39
Thus the two number are 39 and 13
